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3 years ago

Write the equation for the vertical line that contains point E(-7, 7).

Mathematics

1 answer:

katrin2010 [14]3 years ago

4 0

I believe that your answer is option b - x = -7

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Please help me I’m so lost

Svetllana [295]

Answer:

759.88 square inches

Step-by-step explanation:

$r = \frac{1}{2}d = \frac{1}{2} \times 44 = 22 \\ \\ area = \frac{1}{2} \pi \: {r}^{2} \\ area = \frac{1}{2} \times 3.14 \times 22 \times 22 \\ area = 759.88 \: square \: inches$

4 0

2 years ago

Read 2 more answers

Segu

Lynna [10]

Answer:

The formula is 10 - 3n

Step-by-step explanation:

For an nth term in an arithmetic sequence

U( n ) = a + ( n - 1)d

Where n is the number of terms

a is the first term

d is the common difference

From the sequence above

a = 7

d = 4 - 7 = - 3

The formula for an nth term is

U(n) = 7 + (n - 1)-3

= 7 - 3n + 3

The final answer is

= 10 - 3n

Hope this helps you.

3 0

2 years ago

The base is 34 ya and it’s height is 20.5. What is the area

aliya0001 [1]

There is no given area without the width dimension

8 0

2 years ago

There are values of t so that sin t=.35 and cos t=.6

NISA [10]

Recall the fundamental rule of trig:

$\sin^2(x)+\cos^2(x)=1 \quad\forall x \in \mathbb{R}$

So, there exists an angle $t$ such that

$(0.6,0.35)=(\sin(t),\cos(t))$

if and only if

$\sin^2(t)+\cos^2(t)=0.6^2+0.35^2=1$

Working out the numbers, we get

$0.6^2+0.35^2=0.36+0.1225=0.4825\neq 1$

So, there doesn't exist a number $t$ such that

$(0.6,0.35)=(\sin(t),\cos(t))$

7 0

2 years ago

Six subtracted from a number

Klio2033 [76]

Answer:

X-6

Step-by-step explanation:

Represent the unknown number with a variable then introduce the minus sign

8 0

2 years ago