Answer: The approximate pressure of the gas after it is heated to 278 K is 0.468 atm.
Explanation:
Given: 
= 178 K, 
= 0.3 atm
= 278 K, 
= ?
According to Gay Lussac law, at constant volume the pressure of a gas is directly proportional to the temperature.
Formula used to calculate the pressure is as follows.
Substitute the values into above formula is as follows.
Thus, we can conclude that the approximate pressure of the gas after it is heated to 278 K is 0.468 atm.
I think it is that they use the same process which is oxidation
Answer:
-145.2kJ
Explanation:
Enthalpy is an extensive property as its value depends on the amount of substance present in the system.
If the enthalpy for one mole of methanol = -726 kJ/mol;
The Enthalpy for 0.2 mol is given as;
Enthalpy = 0.200 * 726
Enthalpy = -145.2kJ
It would take -145.2kJ for 0.200 mol of methanol to undego the combustion reaction.
Answer:
Id say A. Competition, hope this helps
Explanation:
What? That docent make any scene?
