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Paraphin [41]
3 years ago
10

How many moles of NO₂ would be required to produce 5.73 moles of HNO₃ in the presence of excess water in the following chemical

reaction?
3 NO₂(g) + H₂O (l) → 2 HNO₃(g) + NO(g)
Chemistry
1 answer:
vivado [14]3 years ago
7 0

Answer:

8.595 mol NO2

Explanation:

5.73 mol HNO3 * (\frac{3 mol NO2}{2 mol HNO3}) = 8.595 mol NO2

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Hydrogen gas and aqueous zinc chloride are produced by the reaction of aqueous hydrochloric acid and solid zinc . Write a balanc
Ymorist [56]

<em>1. Write out all the ions/elements and indicate whether they are reactants or products. </em>

<u>Reactants:</u>

Aqueous Hydrochloric Acid: HCl (H has a charge of +1 and Cl has a charge of 1-, so when an ionic bond forms they will form HCl).

Solid Zinc: Zn (since it is a solid zinc with no other forms of elements, the zinc is pure).

<u>Products:</u>

Hydrogen gas: H2 (it has to be H2 because Hydrogen is a diatomic element, and when by itself during reactions, will be H2 instead of H).

Aqueous Zinc Chloride: ZnCl2 (Zn has a charge of 2+ and Cl has a charge of 1-, so through an ionic bond, they will form ZnCl2).

<em>2. Using this information, you can then write out the unbalanced equation.</em>

HCl + Zn -> H2 + ZnCl2

<em>3. Next, indicate their states of matter and any aqueous solutions. </em>

HCl (aq) + Zn (s) -> H2 (g) + ZnCl2 (aq)

<em>4. Try different numbers until you get the same numbers of H, Cl, and Zn on both sides. </em>

2 HCl (aq) + Zn (s) -> H2 (g) + ZnCl2 (aq)

As you can see, the equation contains 2 Hydrogen atoms on both sides, 2 Chloride atoms on both sides, and 1 Zinc atom on both sides. The equation is chemically balanced.

5 0
4 years ago
Element 1 has 1 valence electron, element 2 has 2 valence electrons, element 3 has 3 valence electrons, element 4 has 4 valence
Morgarella [4.7K]
Element because its closer to having 8
8 0
4 years ago
What is the difference between 0.50 mol HCl and 0.50 M HCl?
iVinArrow [24]

Answer:

Here you go

Explanation:

6 0
3 years ago
The Mole #2<br> Avogadro's Number <br> PLEASE HELP ASAP! due tmr will give brainliest!
Elis [28]

The solution is here,

given mass of copper wire(m)=25 g

no. of moles in given mass of Cu=0.393

a) no. of atoms= no. of moles×avogardo's number

=0.393×6.023×10^23=2.36 ×10^23 atoms

b) 25 g of Cu wire has 0.393 moles

so 200 g of Cu wire has 0.393/25 × 200=3.144 mol.

no. of atoms= 3.144×2.023×10^23=1.89×10^24 atoms.

c) 25 g of Cu wire has 2.36×10^23 atoms

so 5 g of Cu wire has (2.36×10^23)/25 × 5

=4.72×10^22 atoms

( b can also be solve like c)

7 0
3 years ago
Carbohydrates are a type of ?
sweet [91]
The answer is glyceride, hope I helped
3 0
3 years ago
Read 2 more answers
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