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MatroZZZ [7]
3 years ago
8

When salt is dissolved in water, which is the solvent and which is the solute

Chemistry
1 answer:
elena55 [62]3 years ago
7 0

Answer:

the solvent is water and the solute is salt

Explanation:

A solute is the component in a solution in the lesser amount. In a NaCl solution, the salt is the solute. A solution may contain more than one solute.

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Explanation:

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Read 2 more answers
How Many Moles Of HCl Need To Be Added To 150.0 ML Of 0.50 M NaZ To Have A Solution With A PH Of 6.50
Aleks04 [339]

The number of mole of HCl needed for the solution is 1.035×10¯³ mole

<h3>How to determine the pKa</h3>

We'll begin by calculating the pKa of the solution. This can be obtained as follow:

  • Equilibrium constant (Ka) = 2.3×10¯⁵
  • pKa =?

pKa = –Log Ka

pKa = –Log 2.3×10¯⁵

pKa = 4.64

<h3>How to determine the molarity of HCl </h3>
  • pKa = 4.64
  • pH = 6.5
  • Molarity of salt [NaZ] = 0.5 M
  • Molarity of HCl [HCl] =?

pH = pKa + Log[salt]/[acid]

6.5 = 4.64 + Log[0.5]/[HCl]

Collect like terms

6.5 – 4.64 = Log[0.5]/[HCl]

1.86 = Log[0.5]/[HCl]

Take the anti-log

0.5 / [HCl] = anti-log 1.86

0.5 / [HCl] = 72.44

Cross multiply

0.5 = [HCl] × 72.44

Divide both side by 72.44

[HCl] = 0.5 / 72.4

[HCl] = 0.0069 M

<h3>How to determine the mole of HCl </h3>
  • Molarity of HCl = 0.0069 M
  • Volume = 150 mL = 150 / 1000 = 0.15 L
  • Mole of HCl =?

Mole = Molarity x Volume

Mole of HCl = 0.0069 × 0.15

Mole of HCl = 1.035×10¯³ mole

<h3>Complete question</h3>

How many moles of HCl need to be added to 150.0 mL of 0.50 M NaZ to have a solution with a pH of 6.50? (Ka of HZ is 2.3 x 10 -5 .) Assume negligible volume of the HCl

Learn more about pH of buffer:

brainly.com/question/21881762

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Why is gold found in the pure state in nature?
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mars1129 [50]

<u>Answer:</u> The balanced chemical equation is 2KClO_3(s)\rightarrow 2KCl(s)+3O_2(g)

<u>Explanation:</u>

A balanced chemical equation is one where all the individual atoms are equal on both sides of the reaction. It follows the law of conservation of mass.

For the given unbalanced chemical equation:

KClO_3(s)\rightarrow KCl(s)+O_2(g)

<u>On the reactant side:</u>

Atoms of K = 1

Atoms of Cl = 1

Atoms of O = 3

<u>On the product side:</u>

Atoms of K = 1

Atoms of Cl = 1

Atoms of O = 2

To balance the equation, we must balance the atoms by adding 2 infront of both KClO_3(s) and KCl(s). Also, a coefficient of 3 must be written infront of O_2(g)

For the balanced chemical equation:

2KClO_3(s)\rightarrow 2KCl(s)+3O_2(g)

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3 years ago
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