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3 years ago

Recursive function f(7)=5.18

Mathematics

1 answer:

Vaselesa [24]3 years ago

6 0

F(7)=5.18
7f=5.8
————
7 7

f=0.74

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1.32:3 1/7 =(1.4y): 5/6

alina1380 [7]

After solving $1.32:3 \frac{1}{7}=(1.4y):\frac{5}{6}$ we get y=0.24

Step-by-step explanation:

We need to solve the ratio: $1.32:3 \frac{1}{7}=(1.4y):\frac{5}{6}$ and find value of y

Solving:

$1.32:3 \frac{1}{7}=(1.4y):\frac{5}{6}$

Converting fractions into decimals

$1.32:3.14=(1.4y):0.83$

Ratio can be written as:

$\frac{1.32}{3.14}=\frac{1.4y}{0.83}$

Now cross multiply

$1.32*0.83=1.4y*3.14$

$1.09=4.39y$

$y=\frac{1.09}{4.39}$

$y=0.24$

So, after solving $1.32:3 \frac{1}{7}=(1.4y):\frac{5}{6}$ we get y=0.24

Keywords: Ratio

Learn more about Ratios at:

#learnwithBrainly

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3 years ago

Diane got a prepaid debit card with $25 on it. For her first purchase with the card, she bought some bulk ribbon at a craft stor

lorasvet [3.4K]

Answer:

Step-by-step explanation:

you can do 25 minus 18.76 then you get 6.24 then divide that by .13 and you get 48

3 0

2 years ago

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Use the equation d=z–9 to find the value of d when z=10.<br><br> d=

denis23 [38]

Step-by-step explanation:

d = z - 9

d = 10 - 9 ----> substitute

d = 1

5 0

3 years ago

Prove that sinxtanx=1/cosx - cosx

maks197457 [2]

Answer:

See below

Step-by-step explanation:

We want to prove that

$\sin(x)\tan(x) = \dfrac{1}{\cos(x)} - \cos(x), \forall x \in\mathbb{R}$

Taking the RHS, note

$\dfrac{1}{\cos(x)} - \cos(x) = \dfrac{1}{\cos(x)} - \dfrac{\cos(x) \cos(x)}{\cos(x)} = \dfrac{1-\cos^2(x)}{\cos(x)}$

Remember that

$\sin^2(x) + \cos^2(x) =1 \implies 1- \cos^2(x) =\sin^2(x)$

Therefore,

$\dfrac{1-\cos^2(x)}{\cos(x)} = \dfrac{\sin^2(x)}{\cos(x)} = \dfrac{\sin(x)\sin(x)}{\cos(x)}$

Once

$\dfrac{\sin(x)}{\cos(x)} = \tan(x)$

Then,

$\dfrac{\sin(x)\sin(x)}{\cos(x)} = \sin(x)\tan(x)$

Hence, it is proved

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3 years ago

What is three-fourths of 1,968

lara31 [8.8K]

All you have to so is divide 1968 by 4.

1968 ÷ 4 = 496.5 = 1/4

Now multiply 496.5 by 3 = 1, 489.5 = 3/4

I hope this helps! :_

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3 years ago

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