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myrzilka [38]
3 years ago
8

What do you expect will occur as air masses move over cold locations? Hot locations? How does this movement of air masses affect

climate? ap environmental science
Chemistry
1 answer:
Maksim231197 [3]3 years ago
3 0

Answer:

Explanation:

When air masses will move over cold location then bottom layer of air cools and become more dense. Due to its high density it is trapped near the ground then it flow towards the equator.

When it moves over hot location then bottom layer gets hot and lighter. Then it moves towards poles.

It changes the temperature and humidity of the climate. making hoter region coll and cooler region a bit hot.

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Mole ratios how can the coefficients in a chemical equation be interpreted
navik [9.2K]

Answer:

The coefficient in a balanced chemical equation  indicates the mole ratio of both reactants and products.  

Explanation:

For example lets consider the reation between Hydrogen and Oxygen to form water:

2H2 + O2 ----------------------- 2H2O

In this reaction, the coefficients of the balanced reaction can be transformed to Mole ratio according to Avogadro's Law which states that at standard temperature and pressure, equal volume of gases contain the same  number of moles.

So the mole ratio for the above equation is  the  ratio of the coefficient:

2moles     :     1 mole               :          2 moles

8 0
2 years ago
Need help on last 3 questions
Olin [163]

Answer:

Explanation:

1)

Given data:

Initial volume of balloon = 0.8 L

Initial temperature = 12°C ( 12+273= 285 K)

Final temperature = 300°C (300+273 = 573 K)

Final volume = ?

Solution:

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 0.8 L .573 K / 285 K

V₂ = 458.4 L / 285

V₂ = 1.61 L

2)

Initial pressure = 204 kpa

Initial temperature = 29°C ( 29 + 273 = 302 K)

Final temperature = ?

Final pressure = 300 kpa

Solution:

P₁/T₁ = P₂/T₂

T₂ = T₁P₂/P₁  

T₂ = 302 K . 300 kpa / 204 kpa

T₂ = 90600 K/ 204

T₂ = 444.12 K

3)

Given data:

Initial volume = 14 L

Initial pressure = 2.1 atm

Initial temperature = 100 K

Final temperature = 450 K

Final volume = ?

Final pressure = 1.2 atm

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂  

V₂ = 2.1 atm × 14 L × 450 K / 100 K × 1.2 atm  

V₂ = 13230 L / 120

V₂ = 110.25 L

5 0
3 years ago
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aliina [53]

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2 years ago
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I would say the answer is C
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