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myrzilka [38]
3 years ago
8

What do you expect will occur as air masses move over cold locations? Hot locations? How does this movement of air masses affect

climate? ap environmental science
Chemistry
1 answer:
Maksim231197 [3]3 years ago
3 0

Answer:

Explanation:

When air masses will move over cold location then bottom layer of air cools and become more dense. Due to its high density it is trapped near the ground then it flow towards the equator.

When it moves over hot location then bottom layer gets hot and lighter. Then it moves towards poles.

It changes the temperature and humidity of the climate. making hoter region coll and cooler region a bit hot.

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Solids, liquids, and gases are three common states of matter. in which of these physical states would a water molecule likely ha
melamori03 [73]
The States of Matter are classified into solid, liquid, and gas. Among these physical states, if we are going to refer to the water molecules, the one that would possess the greatest energy is gas. If you would take the energy of gas, this would become liquid. The answer is option C.
8 0
3 years ago
Which of the following does not serve as a way to neutralize the charge in a body?
MrRa [10]

Answer:

B. Adding more protons to a positively charged body until the number of protons matches the number of electrons.

Explanation:

7 0
3 years ago
What is the partial pressure of helium gas in a mixture that contains 8.00 grams of helium and 8.60 mol argon gas with a total p
Agata [3.3K]

Answer:

P_{He}=9.06torr

Explanation:

Hello there!

In this case, we can identify the solution to this problem via the Dalton's rule because the partial pressure of helium is given by:

P_{He}=x_{He}P_T

Whereas the mole fraction of helium is calculated by firstly obtaining the moles and then the mole fraction:

n_{He}=8.00g\frac{1mol}{4.00g}=2.00mol\\\\ x_{He}=\frac{n_{He}}{n_{He}+n_{Ar}} \\\\ x_{He}=\frac{2.00mol}{2.00mol+8.60mol}\\\\x_{He}=0.189

Then, we calculate the partial pressure as shown below:

P_{He}=0.189 *48.0torr\\\\P_{He}=9.06torr

Best regards!

4 0
3 years ago
The activation barrier for the hydrolysis of sucrose into glucose and fructose is 108 kJ/mol. Part A If an enzyme increases the
emmasim [6.3K]

Answer:

The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme

Explanation:

From the given information:

The activation barrier for the hydrolysis of sucrose into glucose and fructose is 108 kJ/mol.

In this  same concentration for the glucose and fructose; the reaction rate can be calculated by the rate factor which can be illustrated from the Arrhenius equation;

Rate factor in the absence of catalyst:

k_1= A*e^{^{^{ \dfrac {- Ea_1}{RT}}

Rate factor in the presence of catalyst:

k_2= A*e^{^{^{ \dfrac {- Ea_2}{RT}}

Assuming the catalyzed reaction and the uncatalyzed reaction are  taking place at the same temperature :

Then;

the ratio of the rate factors can be expressed as:

\dfrac{k_2}{k_1}={  \dfrac {e^{ \dfrac {- Ea_2}{RT} }} { e^{ \dfrac {- Ea_1}{RT} }}

\dfrac{k_2}{k_1}={  \dfrac {e^{[  Ea_1 - Ea_2 ] }}{RT} }}

Thus;

Ea_1-Ea_2 = RT In \dfrac{k_2}{k_1}

Let say the assumed temperature = 25° C

= (25+ 273)K

= 298 K

Then ;

Ea_1-Ea_2 = 8.314 \  J/mol/K * 298 \ K *  In (10^6)

Ea_1-Ea_2 = 34228.92 \ J/mol

\mathbf{Ea_1-Ea_2 = 34.23 \ kJ/mol}

The barrier has to be 34.23 kJ/mol lower when the sucrose is in the active site of the enzyme

8 0
3 years ago
What will happen if you add more solute to a saturated solution?
Annette [7]
No more solute will dissolve at that temperature, the temperature would have to be increased in order for more solute to dissolve.
4 0
4 years ago
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