Keywords:
<em>Equation, variable, value, clear
</em>
For this case we have an equation with a variable of the form
. Where
. Given the value of
, we want to find the value of the variable "x". So, we have:

We must clear "x", for this, we add "19" to both sides of the equation:

We divide between "3" on both sides of the equation:

Thus, the value of the variable "x" is 30.
Answer:

Option A
Using the identity :
Cos (2a) = 1-2 Sin^2(a)
Therefore :<span>1−2 sin ^2 (22.5∘) = Cos(2a)
= Cos (2 * 22.5) = Cos 45</span>
Answer:
Part A: chosen method is by factoring
Part B: First rewrite the equation by writing -24 as a difference so you get x² -9x - 15x + 135 = 0. Then factor out the x and the -15 from the equation so you get x(x-9) - 15(x-9) = 0. Then factor out x-9 from the equation so you have (x-9)(x-15) = 0. Finally, set each expression to 0: x-9=0 and x-15=0 and then solve: x=9 and x=15
Part C: x=9, x=15