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boyakko [2]
4 years ago
10

Why are most organic compounds nonconducting and insoluble in water?

Chemistry
2 answers:
Aleks04 [339]4 years ago
7 0

Explanation:

It is known that like dissolves like which means that polar substances are able to dissolve only in polar solvents.

Whereas non-polar substances are able to dissolve only in non-polar solvents.

As all organic compounds are non-polar in nature so, they are only soluble in non-polar solvents.

On the other hand, water is a polar solvent and its dissolves substances like NaCl, MgCl_{2} etc that are also polar in nature.

Also, for a solution to conduct electricity it is necessary that there must be flow of ions from one place to another. But a non-polar or organic substance do not dissociate into ions when dissolved in water.

Hence, it is unable to conduct electricity.

Thus, we can conclude that most organic compounds are non-conducting and insoluble in water because:

  • Most organic compounds don't dissolve in water because they are nonpolar.
  • They don't conduct electricity because they are covalent, not ionic.
maksim [4K]4 years ago
4 0
I think the correct answers from the choices listed above are the second and the last options. Organic compounds are nonducting and insoluble in water because of the bonds that these compounds contain. Most organic compounds don't dissolve in water because they are nonpolar. They don't conduct electricity because they are covalent, not ionic.
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MnSO₄.7H₂O

Explanation:

To solve this question, we need to convert the mass of the dehydrated MnSO₄. The difference between mass of the hydrate and dehydrated compound is the mass of water. With the mass we can find the moles of water and the formula of the hydrate:

<em>Moles MnSO₄ -Molar mass: 151g/mol-:</em>

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<em>Moles H₂O -Molar mass: 18g/mol-:</em>

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The ratio of moles MnSO₄: Moles H₂O represent the amount of water molecules in the hydrate:

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<h3>MnSO₄.7H₂O</h3>
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Upon combustion, a 1.3109 g sample of a compound containing only carbon, hydrogen, and oxygen produces 3.2007 g<img src="https:/
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Answer:

The answer to your question is:   C₃H₃O  This is my answer.

Explanation:

Data

Sample = 1.3109 g

CxHyOz

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H₂O = 1.3102 g

Empirical formula = ?

MW CO2 = 44 g

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For Carbon

                                     44 g -------------------- 12 g

                                     3.2007 g ------------    x

                                      x = (3.2007 x 12) / 44

                                      x = 0.8729 g of Carbon

                                     12 g of C --------------  1 mol

                                     0.8729 g --------------  x

                                     x = (0.8729 x 1) / 12

                                     x = 0.0727 mol of Carbon

For Hydrogen

                                 18 g ---------------------- 1 g

                              1.3102 g -------------------  x

                                   x = (1.3102 x 1) / 18

                                  x = 0.0727 g of Hydrogen                                      

                                  1 g ------------------------ 1 mol

                                  0.0727g ----------------  x

                                  x = (0.0727 x 1)/1

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For oxygen

                    g of Oxygen = g of sample - g of Carbon - g of hydrogen

                    g of Oxygen = 1.3109 - 0.8709 - 0.0727

                    g of Oxygen = 0.3673

                                  16 g of Oxygen ------------- 1 mol of O

                                  0.3673 g ---------------------   x

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Divide by the lowest number of moles

Carbon              0.0727 / 0.023  = 3.1  ≈ 3

Hydrogen         0.0727 / 0.023 = 3.1  ≈ 3

Oxygen             0.0230 / 0.023 = 1

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