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boyakko [2]
3 years ago
10

Why are most organic compounds nonconducting and insoluble in water?

Chemistry
2 answers:
Aleks04 [339]3 years ago
7 0

Explanation:

It is known that like dissolves like which means that polar substances are able to dissolve only in polar solvents.

Whereas non-polar substances are able to dissolve only in non-polar solvents.

As all organic compounds are non-polar in nature so, they are only soluble in non-polar solvents.

On the other hand, water is a polar solvent and its dissolves substances like NaCl, MgCl_{2} etc that are also polar in nature.

Also, for a solution to conduct electricity it is necessary that there must be flow of ions from one place to another. But a non-polar or organic substance do not dissociate into ions when dissolved in water.

Hence, it is unable to conduct electricity.

Thus, we can conclude that most organic compounds are non-conducting and insoluble in water because:

  • Most organic compounds don't dissolve in water because they are nonpolar.
  • They don't conduct electricity because they are covalent, not ionic.
maksim [4K]3 years ago
4 0
I think the correct answers from the choices listed above are the second and the last options. Organic compounds are nonducting and insoluble in water because of the bonds that these compounds contain. Most organic compounds don't dissolve in water because they are nonpolar. They don't conduct electricity because they are covalent, not ionic.
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3 years ago
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<h2>Answer:</h2>

Nucleus.

<h2>Explanation:</h2>
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Calculations

1. Temperature in kelvins

\begin{array} {rcl}pV & = & nRT\\\text{1.25 atm} \times \text{25.0 L} & = & \rm\text{2.10 mol} \times 0.08206 \text{ L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times T\\31.25&=&0.09847T\text{ K}^{-1}\\T& = &\dfrac{31.25}{\text{0.098 47 K}^{-1}}\\\\& = &\text{181 K}\end{array}

2. Temperature in degrees Celsius

\begin{array} {rcl}T & = & (181 - 273.15) \, ^{\circ}\text{C}\\& = & -92 \, ^{\circ}\text{C}\\\end{array}\\\text{The temperature of the gas is $\large \boxed{\mathbf{-92 \, ^{\circ}}\textbf{C}}$}

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