Explanation:
An object in motion <u>stays</u> <u>at</u> motion An object <u>at</u> <u>rest</u> stays at rest unless acted by an <u>external</u> force.
[ Newton's 1st law of motion ]
The reactant is Mercury (II) Oxide while the products are Mercury and Oxygen separately.
This is because the reactants are typically always on the left side of the yields symbol. In this decomposition reaction, it would still be the same as at the end of the reaction, there were to products produced: Mercury and Oxygen.
Products tend to always be on the right side of the yields symbol, they're what comes out of a reaction no matter what type.
Hope this helps!
Answer:
70.77 g/mol is the molar mass of the unknown gas.
Explanation:
Effusion is defined as rate of change of volume with respect to time.
Rate of Effusion=
Effusion rate of oxygen gas after time t = 
Molar mass of oxygen gas = M = 32 g/mol
Effusion rate of unknown gas after time t = 
Molar mass of unknown gas = M'
The rate of diffusion of gas, we use Graham's Law.
This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows:



M' = 70.77 g/mol
70.77 g/mol is the molar mass of the unknown gas.
Answer:
650 grams
Explanation:
Given that acetylene gas reacts with oxygen to produce caobon dioxide, water and heat and the unbalnced equation is

Gram-formula mass of
g/mol
So, mass of 1 mole of acelylene is 26 grams
Therefore, mass of 25 moles of acelylene=25x26=650 grams
Hence, the mass of 25 moles of acelylene is 650 grams
Answer:The difference between seed plants and seedless plants is that seedless plants do not bear seeds for propagation, whereas seed plants bear seeds for multiplication.
Explanation: