Answer: amount = 2466.95L
Explanation:
given that the speed is = 1900./kmh i.e. 1hr/900km
distance = 1050km
the fuel burns at a rate of 74.4 L/min
therefore the amount of fuel that the jet consumes on a 1050.km becomes;
total fuel used = time × fuel burning rate
where time = distance / speed
∴ total fuel used (consumed) = time × fuel burning rate
total fuel consumed = (1050km × 1hr/1900km) × (60min/ 1hr × 74.4L/1min)
total fuel consumed = 2466.95L
This is a Charles' Law problem: V1/T1 = V2/T2. As the temperature of a fixed mass of gas decreases at a constant pressure, the volume of the gas should also decrease proportionally. Here, we are given the new volume of the gas after cooling, and we want to determine to what temperature the gas was cooled.
To use Charles' Law, the temperature must be in Kelvin (x °C = x + 273.15 K). We want to solve Charles' Law for T2, which we can obtain by rearranging the equation into T2 = V2T1/V1. Given V1 = 130 L, T1 = 250 °C (523.15 K), and V2 = 85 L:
T2 = (85 L)(523.15 K)/(130 L) = 342 K or 68.9 °C. If sig figs are to be considered, since all the values in the question are given to two sig figs, the answer to two sig figs would be either 340 K or 69 °C.
We are given with the mass of Arsine (
The mass of arsine is 15g
there is a relation between moles, mass and molar mass of any compound which is
The molar mass of Arsine = atomic mass of As + 3X atomic mass of H
the molar mass of Arsine = 74.92 + 3X 1 = 77.92 g/mol
Let us calculate the moles as
Answer:
Explanation:
The answer is 9.03 × 10²⁴ molecules.
Avogadro's number is the number of units (atoms, molecules) in 1 mole of substance.
Make the proportion.
6.02 × 10²³ molecules per 1 mol
x per 15 mol
6.02 × 10²³ molecules : 1 mol = x : 15 mol
x = 6.02 × 10²³ molecules * 15 mol * 1 mol
x = 90.3 × 10²³ molecules
x = 9.03 × 10 × 10²³ molecules
x = 9.03 × 10²³⁺¹ molecules
x = 9.03 × 10²⁴ molecules