Explanation:
Dehydrohalogenation reactions occurs as elimination reactions through the following mechanism:
Step 1: A strong base(usually KOH) removes a slightly acidic hydrogen proton from the alkyl halide.
Step 2: The electrons from the broken hydrogen‐carbon bond are attracted toward the slightly positive carbon (carbocation) atom attached to the chlorine atom. As these electrons approach the second carbon, the halogen atom breaks free.
However, elimination will be slower in the exit of Hydrogen atom at the C2 and C3 because of the steric hindrance by the methyl group.
Elimination of the hydrogen from the methyl group is easier.
Thus, the major product will A
C. A person pushing a box across the floor
Answer:
This should help you with your problem
<span>Although Uranium (U) comes in many isotopes, Uranium has the same atomic number which is 92. The three naturally occurring isotopes of Uranium includes: U-233, U-236-, U-232. Other isotopes of Uranium are U-235 and U-238. All isotopes of Uranium comes in different atomic masses, yet, all atoms of Uranium will always be 92.</span><span />
Answer:
-20 kcal/mol
Explanation:
In a reaction, enzymes reduces the energy of activation, but they have no effect on the Gibb's free energy of reaction. The free energy of the product is the same as it would be without the enzyme. Thus, the enzyme does not affect the free energy of the reaction. Mathematically
Gibb free energy = Enthalpy - temperature x change in entropy
Note that from the relation above, enzyme is not a factor nor is activation energy a factor.
