Relative dating is used to arrange geological events….
Relative dating puts geologic events in chronological order without requiring that a specific numerical age be assigned to each event….
Relative Dating uses the half life of isotopes to get the exact age of a rock or mineral.
Motion is detected when an object changes its position with respect to a reference point. Coordinate system is basically used to represent motion. A coordinate system uses numbers or coordinates which represent position of the reference points on a two-dimensional or three-dimensional space. The trajectory of a point or line can be studied on a coordinate system which describes various aspects of motion like velocity, acceleration, distance, displacement etc. Coordinate system is important because it helps to choose a starting point and the direction (which will be positive).
<span>During their embryonic stage they have a flexible cord that supports their bodies which disappears in the adult stage. Some of these develop bones surrounding the cord in the adult stage rather than have it disappear.</span>
First of all, we have to sort out how this situation is put together. You have 55 kg that's hanging suspended, but it's tied to another 65 kg on a horizontal ledge. Somewhere in there, the rope has to turn a corner. Obviously, it has to go around the edge of the ledge, and we have top assume that there's absolutely no friction against the rope at that point, because we're not told anything different. So we have to treat the edge like a frictionless pulley. And we're also going to ignore the weight of the rope.
OK. The weight of the 55-kg guy who is hanging suspended is (mass) x (gravity) =
(55 x 9.8) = 539 newtons. That force soaks upward through the rope, makes the turn
at the edge, and is exerted horizontally against the 65-kg guy on the ledge.
Hopefully, the suspended guy can hold on for a few minutes longer, while we analyze
the forces around the heavier guy up on the ledge.
The weight of the guy on the ledge is (mass) x (gravity) = (65 x 9.8) = 637 newtons.
That's his weight, pointing downward, against the ledge.
As his boots slip along the ledge, the friction force against his motion is
(his weight) x (the coefficient of kinetic friction between him and the ledge) =
(637 newtons) x (0.45) = 286.65 newtons.
The man on the ledge has the rope pulling him toward the edge with 539N of force,
and 286.65N of friction force holding him back. You can see that he's slipping toward
the edge, because the friction force isn't enough to hold him.
The net force on him is (539N forward) + (286.65N backward) = 252.35N forward.
Since the man on the ledge has a net force pulling him forward toward the edge,
he accelerates in that direction.
Force = (mass) x (acceleration)
Acceleration = (force) / (mass) = (252.35N) / (65kg) = <em><u>3.88 meters per second²</u></em>
He's sliding toward the edge with an acceleration of about 0.396 G ... his speed is increasing about 39 or 40% as fast as it will after he falls over the edge, and the both of them proceed toward their ultimate and apparently unavoidable 'splut' below.
I've totally terrified myself answering this one.
Answer:
x = 27.3 m
Explanation:
This is a projectile launching exercise, let's start by looking for the time it takes for the rock to reach the height of the window.
Let's use trigonometry to find the velocities of the rock
sin 40 = / v
cos 40 = v₀ₓ / v
v_{oy}= v sin 40
v₀ₓ = v cos 40
v_{oy} = 30 sin 40 = 19.28 m / s
v₀ₓ = v cos 40
v₀ₓ = 30 cos 40 = 22.98 m / s
we look for the time
= v_{oy}^2 - 2 g y
v_{y}^2 = 19.28 2 - 2 9.8 16 = 371.71 - 313.6 = 58.118
v_{y} = 7.623 m / s
we calculate the time
v_{y} = v_{oy} - gt
t = (v_{oy} - v_{y}) / g
t = (19.28 -7.623) / 9.8
t = 1,189 s
since the time is the same for both movements let's use this time to find the horizontal distance
x = v₀ₓ t
x = 22.98 1,189
x = 27.3 m