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3 years ago

With mechanical waves, what is moving and what stays in roughly the same place?

Physics

1 answer:

Zielflug [23.3K]3 years ago

6 0

The part that moves are called anti-nodes. The stationary pars are nodes

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) a box weighing 77.0 n rests on a table. a rope tied to the box runs vertically upward over a pulley and a weight is hung from

sineoko [7]

Refer to the diagram shown below.

T = the tension in the rope
N = the the normal reaction (the force that the table exerts on the box)
W = the hanging weight

Assume that the pulley is frictionless.
For equilibrium,
T = W
and
T + N = 77

Therefore
N = 77 - W

(a) When W = 30 N,
N = 77 - 30 = 47 n
Answer: 47 N

(b) When W = 60 N,
N = 77 - 60 = 17 N
Answer: 17 N

(c) When W = 90 N
N = 77 - 90 = - 13 N
There is no normal reaction, and the system is no longer in equilibrium.
Instead, the box will be lifted by a force of 13 N, and the box will accelerate upward.

8 0

3 years ago

A bus travels 6 km east and then 8 km south. The magnitude of the bus’s resultant displacement is ___km.

Crank

Answer:

10 km

Explanation:

You can draw your problem out. You can use the pathagoran theorem to figure it out. So $6^{2}$ + $8^{2}$ and then square root the answer which will be $\sqrt{100}$ which equals to 10.

3 0

3 years ago

Which is the SI base unit for distance?

stealth61 [152]

Yes you're correct. For distance, SI is based on meters.

7 0

3 years ago

A penguin slides at a constant velocity of 3.57 m/s down an icy incline. The incline slopes above the horizontal at an angle of

igomit [66]

Answer:t=0.81 s

Explanation:

Given

Penguin slides down with constant velocity of 3.57 m/s

as the Penguin Slides with constant velocity therefore $F_{net}$ is zero on Penguin

$F_{net}=mg\sin \theta -f_r$

$f_r=$ friction Force

$f_r=\mu mg$

$\mu =$ coefficient of Kinetic friction

$mg\sin \theta =\mu mg$

$\tan \theta =\mu$

$\mu =\tan 9.85=0.45$

after reaching on floor final velocity of penguin will be zero after time t

thus

$v=u+at$

here $a=\mu g$

$a=0.45\times 9.8=4.41$ (deceleration)

$0=3.57-4.41\times t$

$t=\frac{3.57}{4.41}=0.809$

$t=0.81 s$

8 0

3 years ago

Show the equation of simple pendulum to be dimensionally consistent

nataly862011 [7]

T is in seconds (s)

2pi is dimensionless 

L is in meters (m) 

g is in meters per second squared (m/s^2) 

so you can write the equation for the period of the simple pendulum in its units... 

s=sqrt(m/(m/s^2)) 

simplify

s=sqrt(m*s^2*1/m) cancelling the m's 

s=sqrt(s^2) 

s=s 

therefore the dimensions on the left side of the equation are equal to the dimensions on the right side of the equation.

6 0

2 years ago