Answer:
σ = 11.68
Step-by-step explanation:


ax²+bx+c=0
4a²x²+4abx+4ac=0
4a²x²+4abx=-4ac
4a²x²+4abx+b²=b²-4ac
(2ax+b)²=b²-4ac
To write an equation in standard form, move each term to the left side of the equation and simplify.
ax2+bx+c = 0ax2+bx+c = 0
Move all the expressions to the left side of the equation.
−17−8x2−4x+3x2 = 0-17-8x2-4x+3x2 = 0
Add −8x2-8x2 and 3x23x2.
−17−5x2−4x = 0-17-5x2-4x = 0
Reorder the polynomial.
5x2+4x+17 = 0
Step-by-step explanation:
I hope this helped-
The correct answers are A C and B
Given:
The two functions are:


To find:
The value of
.
Solution:
We have,


We know that,


![(h\circ g)(b)=[(5b-9)-1]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28b%29%3D%5B%285b-9%29-1%5D%5E2)
![(h\circ g)(b)=[5b-10]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28b%29%3D%5B5b-10%5D%5E2)
Putting
, we get
![(h\circ g)(-6)=[5(-6)-10]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D%5B5%28-6%29-10%5D%5E2)
![(h\circ g)(-6)=[-39-10]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D%5B-39-10%5D%5E2)
![(h\circ g)(-6)=[-49]^2](https://tex.z-dn.net/?f=%28h%5Ccirc%20g%29%28-6%29%3D%5B-49%5D%5E2)

Therefore, the value of
is 2401.