Answer:
Maximization and Minimization Problems on Feasible Regions
Step-by-step explanation:
go to that yt vid
Answer:
I don't see a polygon anywhere...
Step-by-step explanation:
Sum of arithmetic terms = n/2 × [2a + (n - 1)×d], where 'a' is the first term, 'd' is the common difference between two numbers, and 'n' is the number of terms.
this is the same as n/2 × (a1 + an), because
an = a1 + (n-1)×d
so, for the series above :
a or a1 = 2
d = 7, as every new term is the previous term plus 7.
for n
37 = a1 + (n-1)×d = 2 + (n-1)×7
and now solve for n
35 = 7n - 7
42 = 7n
n = 6
so, the sum of all terms is
6/2 × (2+37) = 3×39 = 117
We have,
t = 6.21 s
s = 111 m
u = 0 m/s
To determine: "a" of the particle.
We know,
s = ut + ½ at²
⇒ s = ½ at²
⇒ a = 2s/t²
⇒ a = [2(111 m)]/(6.21 s)²
⇒ a = (222 m)/(38.5641 s²)
⇒ a ≈ 5.75 m/s²
