In a ____ number, each digit can have only one of two possible values: 0 or 1.

-Dominant- [34]

First thing to do, when you have to add 2 fractions, you have to make both denominators equal. 14/6 = 0.84, so can't multiply or divide any fraction by a whole number to get the other denominator.
So, you multiply each fraction by the denominator of the other fraction. Which means that you multiply 5/14 by the denominator of 1/6 which is 6, and you multiply 1/6 by the denominator of 5/14 which is 14.
5/14 + 1/6 = 30/84 + 14/84
Then you join both fractions to make them under one denominator, since both denominators are equal.
30/84 + 14/84 = (30+14)/84 = 44/84.
Now, you need to simplify the fraction: you divide both numerator and denominator by 4:
44/84 = 11/21

So 5/14 + 1/6 = 11/21

Hope this Helps! :)

6 0

3 years ago

Read 2 more answers

"Suppose an object falling in the atmosphere has mass m=15kg and the drag coefficient is γ=9kg/s. Recall that the differential e

Art [367]

Answer:

a. v(t)= -6.78 $e^{-16.33t}$ + 16.33 b. 16.33 m/s

Step-by-step explanation:

The differential equation for the motion is given by mv' = mg - γv. We re-write as mv' + γv = mg ⇒ v' + γv/m = g. ⇒ v' + kv = g. where k = γ/m.Since this is a linear first order differential equation, We find the integrating factor μ(t)= $e^{\int\limits^ {}k \, dt }$ = $e^{kt}$ . We now multiply both sides of the equation by the integrating factor.

μv' + μkv = μg ⇒ $e^{kt}$ v' + k $e^{kt}$ v = g $e^{kt}$ ⇒ [v $e^{kt}$ ]' = g $e^{kt}$ . Integrating, we have

∫ [v $e^{kt}$ ]' = ∫g $e^{kt}$

v $e^{kt}$ = $\frac{g}{k}$ $e^{kt}$ + c

v(t)= $\frac{g}{k}$ + c $e^{-kt}$ .

From our initial conditions, v(0) = 9.55 m/s, t = 0 , g = 9.8 m/s², γ = 9 kg/s , m = 15 kg. k = y/m. Substituting these values, we have

9.55 = 9.8 × 15/9 + c $e^{-16.33 * 0}$ = 16.33 + c

c = 9.55 -16.33 = -6.78.

So, v(t)= 16.33 - 6.78 $e^{-16.33t}$ . m/s = - 6.78 $e^{-16.33t}$ + 16.33 m/s

b. Velocity of object at time t = 0.5

At t = 0.5, v = - 6.78 $e^{-16.33 x 0.5}$ + 16.33 m/s = 16.328 m/s ≅ 16.33 m/s

6 0

2 years ago

Solve for [x]. The polygons in each<br> 2x-20<br> 16<br> 16<br> 8

Nataly_w [17]

$\quad \huge \quad \quad \boxed{ \tt \:Answer }$

$\qquad \tt \rightarrow \:x = 16$

____________________________________

$\large \tt Solution \: :$

If two polygons are similar, their corresponding sides ratios will be equal to each other.

$\qquad \tt \rightarrow \: \cfrac{8}{16} = \cfrac{2x - 20}{24}$

$\qquad \tt \rightarrow \: \cfrac{1}{2} = \cfrac{2x - 20}{24}$

$\qquad \tt \rightarrow \: 2x - 20 = \cfrac{24}{2}$

$\qquad \tt \rightarrow \: 2x = 12 + 20$

$\qquad \tt \rightarrow \: 2x = 32$

$\qquad \tt \rightarrow \: x = 16$

Answered by : ❝ AǫᴜᴀWɪᴢ ❞

7 0

1 year ago

What is the sum of three tenths plus thirty nine hundredths equals blank a thirty six hundredths b forty two hundredths c sixty

ad-work [718]

Answer:c- sixty nine hundredths

Step-by-step explanation:

three tenths can be expressed in decimal as 3/10

thirty nine hundredths can be expressed in decimal as 39/100

Therefore the sum of three tenths plus thirty nine hundredths equals

3/10 +39/100

We first find the l.c.m of the two fractions equals 100 so we have 100 as the denominator

then 100 divided by 10 multiplied by 3 +100 divided by 100 multiplied by 39 as illustrated below gives the answer

3/10 +39/100

=30+39/100

=69/100= sixty nine hundredths

3 0

2 years ago

Find the value of x, 110°, 4x+2, and if you can help with steps that would be great :,)

Helen [10]

Answer:

x = 17

Step-by-step explanation:

The two angles with measures form a linear pair and are supplementary.

The measures of supplementary angles has a sum of 180°.

If you add the two given measures, the sum must equal 180°.

4x + 2 + 110 = 180

4x + 112 = 180

4x = 68

x = 68/4

x = 17

7 0

2 years ago