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Softa [21]
3 years ago
9

In a wide area network (WAN), how would you troubleshoot an issue with the domain name system (DNS)?

Computers and Technology
2 answers:
ddd [48]3 years ago
5 0

Answer:

Get the help of someone with specialized knowledge in the area.

Explanation:

APEX Verified

NISA [10]3 years ago
3 0
<span>C. Get the help of someone with specialized knowledge in the area.</span>
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Sean works for a company that ships hospital equipment. He needs to calculate the weight of the items being shipped. He enters t
Anika [276]

Answer:

= A1 * (A2 + A3)

Explanation:

In order to calculate the total weight of the equipment, he would need to first add the total weight of each item. This is done by adding the weight of the item by the weight of the packaging. Once you have this amount you can multiply this value by the total number of items being shipped and that should give you the total weight of the shipment. Using the cells, this can be calculated with the following formula in Excel...

= A1 * (A2 + A3)

7 0
3 years ago
Find the maximum value and minimum value in milesTracker. Assign the maximum value to maxMiles, and the minimum value to minMile
ryzh [129]

Answer:

Following are th program in the C++ Programming Language.

#include <iostream>//set Header files

using namespace std;//set namespace

//define main function

int main()

{

//set integer constants variable

const int NUM_ROWS = 2;

//set integer constants variable

const int NUM_COLS = 2;

//set integer type array

int milesTracker[NUM_ROWS][NUM_COLS];

//set integer type variable and initialize to 0

int i = 0;

//set integer type variable and initialize to 0

int j = 0;

//set integer type variable and initialize to -99

int maxMiles = -99;

//set integer type variable and initialize to -99

int minMiles = -99;

//initialize the value in the two dimensional array

milesTracker[0][0] = -10;

milesTracker[0][1] = 20;

milesTracker[1][0] = 30;

milesTracker[1][1] = 40;

//here is the solution  

maxMiles = milesTracker[0][0];

minMiles = milesTracker[0][0];

/*set for loop to find the minimum miles and maximum miles*/

for (i = 0; i < NUM_ROWS; i++)

{

 for (j = 0; j < NUM_COLS; j++)

 {

 //set if condition for maxMiles is the bigger than

   if (milesTracker[i][j] > maxMiles)

   //initialize milesTracker[i][j] to maxMiles

     maxMiles = milesTracker[i][j];

   //set if condition for minMiles is the smaller than

   if (milesTracker[i][j] < minMiles)

   //initialize milesTracker[i][j] to maxMiles

     minMiles = milesTracker[i][j];

 }

}

//print output

cout << "Min miles: " << minMiles << endl;

//print output

cout << "Max miles: " << maxMiles << endl;

return 0;

}

<u>Output:</u>

Min miles: -10

Max miles: 40

Explanation:

Here, we define the main method and inside it:

  • set two constant integer type variable and initialize to 2
  • set integer type two-dimensional array and pass constant variables in it.
  • Set two integer type variable and initialize to 0 then, again set two integer type variable and initialize to -99.
  • Initialize the values in the two-dimensional array.
  • Set two for loop for the two-dimensional array to find the minimum and maximum miles.
  • Set two if condition to find bigger or smaller miles.

Finally, print the maximum and the minimum miles then, return 0.

6 0
3 years ago
Where is the "delete account" button in my profile? And please give me a legit answer and not just a word.
N76 [4]

Answer:

in your profile for brainley ??

3 0
2 years ago
Read 2 more answers
Which of the following is an accurate statement? When the LOWER function is used in a SELECT clause, it will automatically store
quester [9]

Answer:

Hi there! The answer is C:

Explanation:

The scope of the LOWER function is limited to the select clause it is being used in. Outside of the select statement, the column will be returned as it is currently present in the database. Using the LOWER function will not automatically store data in lower case letters in the database tables. As an exercise, try creating a simple database table called "Employees" with columns "id" and "name". Then input a row using an insert statement with id as 1 and name as "BLAH". Try using the select statement with LOWER function and then without the LOWER statement.

5 0
2 years ago
Recall that the name of a transport-layer packet is segment and that the name of a link-layer packet is frame. What is the name
AlladinOne [14]

Answer:

A network-layer packet is a data gram. A router forwards a packet based on the packet's IP (layer 3) address. A link-layer switch forwards a packet based on the packet's MAC (layer 2) address.

Explanation:

When the end system receives the unstructured bit stream from the physical wire, each layer removes the header information applicable to it until the application receives the data.

1. An application, such as an email program, creates data that will be sent by an end user, such as an email message. The Application layer places a header (encapsulation) field that contains information such as screen size and fonts, and passes the data to the Presentation layer.

2. The Presentation layer places layer 6 header information. For example, the text in the message might be converted to ASCII. The Presentation layer will then pass the new data to the Session layer (layer 5).

3. The Session layer follows the same process by adding layer 5 header information, such as information that the Session layer will manage the data flow, and passes this data to the Transport layer (layer 4).

4. The Transport layer places layer 4 information, such as an acknowledgement that the segment was received in the header, and passes it to the Network layer (layer 3).

5. The Network layer places layer 3 header information, such as the source and destination address so the Network layer can determine the best delivery path for the packets, and passes this data to the Data Link layer (layer 2).

6. The Data Link layer places layer 2 header and trailer information, such as a Frame Check Sequence (FCS) to ensure that the information is not corrupt, and passes this new data to the Physical layer (layer 1) for transmission across the media.

7. The bit stream is then transmitted as ones and zeros on the Physical layer. It is at this point that the Physical layer ensures bit synchronisation. Bit synchronisation will ensure the end user data is assembled in the correct order it was sent.

8. Steps 1 through 7 occur in reverse order on the destination device. Device B collects the raw bits from the physical wire and passes them up the

Data Link layer. The Data Link layer removes the headers and trailers and passes the remaining information to the Network layer and so forth until data is received by the Application layer. Eventually, Device B will receive an email notification displaying a message to indicate that a new email message has been received.

5 0
3 years ago
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