Answer:
Either one of these.
Step-by-step explanation:
volumepile=1/3 (PI r^2)h
but r=h/2, so
volume=1/12 PI h^3
dv/dt=10 ft^3/min
but dv/dt=1/12 PI 3h^2 dh/dt
solve for dh/dt
This assumes you mean by "altitude" the height. If you mean altitude as slant height, you have to adjust the fromula
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given: r = h/2
V = (1/3)π r^2 h
= (1/3)π (h/2)^2 (h)
= (1/12) π h^3
dV/dt = (1/4)π h^2 dh/dt
for the given data ...
10 = (1/4)π(25)dh/dt
dh/dt = 10(4)/((25π) = 1.6/π feet/min
Answer:
Y = 6,8 X = -6,3 Z = -2, -1
Y = 9,7 X = -3,2 Z = 1,-2
Step-by-step explanation:
The answer for your question is B. 5
That's a hard one either c or d
Answer:
csc (- Ф) = -29/20
Step-by-step explanation:
We know that:
csc Ф = 1/ sinФ ................. equation 1
csc (- Ф) = - csc Ф .............equation 2
Given that:
sin Ф = 20/29
Using equation 1:
csc Ф = 1/ (20/29)
csc Ф = 29/20
using equation 2:
csc (-Ф) = - csc Ф = -29/20
I hope it will help you!
