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12345 [234]
4 years ago
10

As magma rises, it carves a tube-shaped structure called a _____.

Physics
2 answers:
creativ13 [48]4 years ago
7 0
I think the correct answer is a d ike. As magma rises, it carves a tube-shaped structure called a d ike. In geology, it is an igneous rock that is formed and cuts across a rock and a result of magma intrusion and cooling of the magma. It is usually in a tube shaped.
Anettt [7]4 years ago
6 0

Answer:

Laccolith

Explanation:

As magma rises, it carves a tube-shaped structure called a _____.

During volcanic explosion, molten magma is released from the core to the surface. Upon solidification the magma cools and solidifies .Laccolith is formed horizontally as a result of this process. Laccolith is formed.  volcano lead to loss of lives and properties.

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A 0.40-kg mass is attached to a spring with a force constant of k = 277 N/m, and the mass–spring system is set into oscillation
valentina_108 [34]

To solve this problem it is necessary to apply the concepts related to the kinetic energy expressed in terms of simple harmonic movement, as well as the concepts related to angular velocity and acceleration and linear acceleration and velocity.

By definition we know that the angular velocity of a body can be described as a function of mass and spring constant as

\omega = \sqrt{\frac{k}{m}}

Where,

k = Spring constant

m = mass

From the given values the angular velocity would be

\omega = \sqrt{\frac{277}{0.4}}

\omega = 26.31rad/s

The kinetic energy on its part is expressed as

E = \frac{1}{2} m\omega^2A^2

Where,

A = Amplitude

\omega = Angular Velocity

m = Mass

PART A) Replacing previously given values the energy in the system would be

E = \frac{1}{2} m\omega^2A^2

E = \frac{1}{2} (0.4)(26.31)^2(3*10^{-2})^2

E= 0.1245J

PART B) Through the amplitude and angular velocity it is possible to know the linear velocity by means of the relation

v = A\omega

v = (3*10^{-2})(26.31)

v = 0.7893m/s

PART C) Finally, the relationship between linear acceleration and angular velocity is subject to

a = A\omega^2

a = (3*10^{-2})(26.31)^2

a = 20.76m/s^2

7 0
3 years ago
A coiled telephone cord forms a spiral with 90.0 turns, a diameter of 1.30 cm, and an unstretched length of 57.0 cm. Determine t
Vinvika [58]

Answer:

2.36 μ H

Explanation:

Given,

Number of turns= 90

diameter = 1.3 cm = 0.013 m

unscratched length = 57 cm  = 0.57 m

Area, A = π r²

            = π x 0.0065² = 1.32 x 10⁻⁴ m²

 we know,

   L = \dfrac{\mu_0N^2A}{l}

   L = \dfrac{4\pi \times 10^{-7}\times 90^2\times 1.32\times 10^{-4}}{0.57}

    L = 2.36 μ H

Hence, the inductance of the unstretched cord is equal to 2.36 μ H

8 0
3 years ago
Two pickup trucks each have a mass of 2,000 kg. The gravitational force between the trucks is 3.00 × 10-5 N. One pickup truck is
levacccp [35]

Answer:

New gravitational force would be: 4.5\,\,\,10^{-5}\,\,\,N

Explanation:

Recall the general form of the gravitational force between two objects of masses m1 and m2 separated a distance "d":

F_g=G\,\frac{m1\,*\, m2}{d^2}

which for the 2000 kg trucks becomes:

F_g=G\,\frac{m1\,*\, m2}{d^2} \\3\,\,\,10^{-5}\,N=G\,\frac{2000\,*\, 2000}{d^2}

when we add 1000 kg of bricks to one truck, we get the following unknown force (x) that we need to find:

F_g=G\,\frac{m1\,*\, m2}{d^2} \\x=G\,\frac{3000\,*\, 2000}{d^2}

Now we divide term by term the last equation by the previous one, in order to cancel out common factors to both equation (G, d^2) and get the following equation:

\frac{x}{3\,\,\,10^{-5}} =\frac{3000}{2000} \\x=\frac{9}{2} \,10^{-5} =4.5\,\,\,10^{-5}\,\,\,N

8 0
3 years ago
What do glucose starch and cellulose have in common
Andreas93 [3]

Answer:

Glucose, starch and cellulose are all carbohydrates.

6 0
3 years ago
The position of a charge in an electric field gives it _____electric
kykrilka [37]

Answer:

The space surrounding a charged object is affected by the presence of the charge; an electric field is established in that space. A charged object creates an electric field - an alteration of the space or field in the region that surrounds it. Other charges in that field would feel the unusual alteration of the space.

Explanation:

5 0
3 years ago
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