X^2+y^2=z^2
x^2+96^2=100^2
x=sqrt(100^2-96^2)
x=28 so the distance from the base of the ladder and the base of the ladder is 28ft.
Hope this helps. Any questions please just ask. Thank you.
The answer is: not likely. There isn’t much of a chance !
I could help if I had a picture of the problem
X/(x+2) = (x+2)/(x+5)
(x+2)^2 = x(x+5)
x^2 + 4x + 4 = x^2 + 5x
x = 4
