All categories

3 years ago

A spring stores 10. joules of elastic potential

2 answers:

6 0

The answer would be . Since we are looking for the spring constant you would need to use the formula
$PEs = \frac{1}{2} k {x}^{2}$
. Then you'd substitute, for PEs and x.
$10j=1/2k(.20m^2).$
Then solve. k=500n/m

serg [7]3 years ago

6 0

<h2>Answer:</h2>

The spring constant is 50 N/m.

<h3>Explanation:</h3>

Spring constant is the specific property of a spring which tells about the stiffness of a spring.

It is the amount of force which is used to displace a spring one meter from its equilibrium position.

Its unit is N/m.

The formula of potential energy in a spring is :

P.E = 1/2Kx2

Here,

P.E = 10 joules

x = 0.2m

K = P.E × 2/x2

K = 10 × 2/0.4

k = 50 N/m

Hence the spring constant is 50 N/m.

You might be interested in

I tried to experiment of dropping candy into a liter of soda and caused a big explosion of foamy soda

Anestetic [448]

Answer:

.....what type of question is this

Explanation:

6 0

2 years ago

In an element's square on the periodic table, the number with the greatest numerical value represents the

Irina-Kira [14]

Answer: Atomic mass

Explanation:

I took the test!

your welcome

8 0

3 years ago

Read 2 more answers

An ideal gas is allowed to expand isothermally from 2.00 l at 5.00 atm in two steps:

Burka [1]

Heat added to the gas = Q = 743 Joules

Work done on the gas = W = -743 Joules

$\texttt{ }$

<h3>Further explanation</h3>

The Ideal Gas Law that needs to be recalled is:

$\large {\boxed {PV = nRT} }$

<em>P = Pressure (Pa)</em>

<em>V = Volume (m³)</em>

<em>n = number of moles (moles)</em>

<em>R = Gas Constant (8.314 J/mol K)</em>

<em>T = Absolute Temperature (K)</em>

Let us now tackle the problem !

$\texttt{ }$

<u>Given:</u>

Initial volume of the gas = V₁ = 2.00 L

Initial pressure of the gas = P₁ = 5.00 atm

<u>Unknown:</u>

Work done on the gas = W = ?

Heat added to the gas = Q = ?

<u>Solution:</u>

<em>Ideal gas is allowed to expand isothermally:</em>

$P_1V_1 = P_2V_2$

$5.00 \times 2.00 = 3.00 \times V_2$

$V_2 = 10 \div 3$

$V_2 = 3\frac{1}{3} \texttt{ L}$

$\texttt{ }$

<em>Next we will calculate the work done on the gas:</em>

$W_A = -P_2(V_2 - V_1)$

$W_A = -3.00(3\frac{1}{3} - 2.00)$

$W_A = \boxed{-4 \texttt{ L.atm}}$

$\texttt{ }$

<em>Using the same method as above:</em>

$P_2V_2 = P_3V_3$

$3.00 \times 3\frac{1}{3} = 2.00 \times V_3$

$V_3 = 10 \div 2$

$V_3 = 5 \texttt{ L}$

$\texttt{ }$

<em>Next we will calculate the work done on the gas:</em>

$W_B = -P_3(V_3 - V_2)$

$W_B = -2.00(5 - 3\frac{1}{3})$

$W_B = \boxed{-3\frac{1}{3} \texttt{ L.atm}}$

$\texttt{ }$

<em>Finally we could calculate the total work done and heat added as follows:</em>

$W = W_A + W_B$

$W = -4 + (-3\frac{1}{3})$

$W = -7\frac{1}{3} \texttt{ L.atm}$

$W = -7\frac{1}{3} \times 101.33 \texttt{ J}$

$\boxed{W \approx -743 \textt{ J}}$

$\texttt{ }$

$\Delta U = Q + W$

$0 = Q + (-743)$

$\boxed{Q = 743 \texttt{ J}}$

$\texttt{ }$

<h3>Learn more</h3>

Minimum Coefficient of Static Friction : brainly.com/question/5884009
The Pressure In A Sealed Plastic Container : brainly.com/question/10209135
Effect of Earth’s Gravity on Objects : brainly.com/question/8844454

$\texttt{ }$

<h3>Answer details</h3>

Grade: High School

Subject: Physics

Chapter: Pressure

5 0

3 years ago

4. The Earth is the only planet that contains storms. Tor F 5. Lightning is a form of energy made up of protons that move from c

Mumz [18]

Answer:

4. F

5. F

Explanation:

jupiter constantly has hurricanes and uranus has storms often too.

lightning can move many ways including from cloud to cloud and even from ground ton sky (seriously look it up it's cool)

6 0

3 years ago

At a temperature of 320K, the gas in a cylinder has a volume of 40.0 liters. If the volume of the gas is decreased to 20.0 liter

Lerok [7]

Assuming the gas behaves ideally,
PV/T = constant. P will also be constant in this giving us:
V₁/T₁ = V₂/T₂
40/320 = 20/T₂
T₂ = 160 K
The answer is A.

6 0

3 years ago

Read 2 more answers