A spring stores 10. joules of elastic potential
2 answers:
The answer would be . Since we are looking for the spring constant you would need to use the formula
. Then you'd substitute, for PEs and x.
Then solve. k=500n/m
<h2>Answer:</h2>
The spring constant is 50 N/m.
<h3>Explanation:</h3>
Spring constant is the specific property of a spring which tells about the stiffness of a spring.
It is the amount of force which is used to displace a spring one meter from its equilibrium position.
Its unit is N/m.
The formula of potential energy in a spring is :
P.E = 1/2Kx2
Here,
P.E = 10 joules
x = 0.2m
K = P.E × 2/x2
K = 10 × 2/0.4
k = 50 N/m
Hence the spring constant is 50 N/m.
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