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Advocard [28]
3 years ago
11

How far away is mars?

Physics
2 answers:
Pachacha [2.7K]3 years ago
8 0

Answer:

Mars, also known as the Red Planet, is 33.9million miles (54.6m kilometres) away from Earth.

Elanso [62]3 years ago
3 0

Answer:

about: 110.14 million mi

Explanation:

the distance to Mars from Earth is 140 million miles (225 million kilometers).But, distance to Mars from Earth is constantly changing.

Hope that was helpful.Thank you!!!

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The water was used to power a generator, creating _______________ energy
Nikitich [7]

Answer:

electric

<em>please give brainliest</em>

3 0
2 years ago
Potential energy calculation - MxGxH. Gravity equals 10. How much
Elena L [17]

Answer:

Ep = 0.6095 [J]

Explanation:

As defined in the problem statement, potential energy is defined as the product of mass by gravity by height. But first we must convert all the values given to measures of the international system (SI)

g = gravity = 10 [m/s^2]

h = elevation = 40 [ft] = 12.19 [m]

m = mass = 5 [g] = 0.005 [kg]

Ep = potential energy [J]

Ep = 0.005*10*12.19 = 0.6095 [J]

8 0
3 years ago
HELP PLEASE
denis-greek [22]
B) Distance: the farther, the weaker!
4 0
3 years ago
Read 2 more answers
On his fishing trip Justin rides in a boat 12 km south. The fish aren’t biting so they go 4 km west. They then follow a school o
In-s [12.5K]
The distance they covered was 17 Km. Not sure that their displacement was though sorry.
6 0
4 years ago
Find the resultant vector (mag. and dir.) given the following information: Ax = 5.7, Ay = 3.4
Mashcka [7]

<u>Answer:</u>

  Magnitude = 6.64

  Direction = 30.82^0 from horizontal.

<u>Explanation:</u>

 We have horizontal component of vector Ax = 5.7 and vertical component of vector Ay = 3.4.

 Magnitude of vector acting perpendicularly = \sqrt{A_x^2+A_y^2}

 Substituting

    A=\sqrt{A_x^2+A_y^2} =\sqrt{5.7^2+3.4^2} =6.64

Direction θ = tan^{-1}(\frac{A_y}{A_x} )

  Substituting

      θ =tan^{-1}(\frac{A_y}{A_x} )= tan^{-1}(\frac{3.4}{5.7})=30.82^0

7 0
3 years ago
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