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Viefleur [7K]
3 years ago
5

0.075 L - 9 mL = _____________ L?

Physics
1 answer:
ss7ja [257]3 years ago
7 0
The answer is .066 L
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A football player kicks a ball with an initial velocity of 25 m/s at an angle of 53 degrees above the horizontal. The vertical c
Verdich [7]

Answer:

20 m/s

Explanation:

initial velocity, u= 25m/s

u has two components. one in horizontal and in one vertical.

so,

u sin theta = vertical component.

=> u sin theta = 25× 4/5

= 20 m/s

7 0
3 years ago
Which of the following have derived units?<br> A. 56 kg<br> B. 2.5 m<br> C. 87 m/s²<br> D. 60 N
photoshop1234 [79]

Answer:

The answer is C!!!!!!!

Becuz meters and seconds are derived into m/s²

Explanation:

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3 years ago
Read 2 more answers
two 2.5 kg balls move away from each other one traveling 3 m/s to the right the other 4 m/s to the left what is the magnitude of
Juli2301 [7.4K]

Answer:

2.5 kg.m/s

Explanation:

Taking left side as positive while right side direction as negative then

Momentum, p= mv where m is the mass of the object and v is the velocity of travel

Momentum for ball moving towards right side=mv=2.5*-3=-7.5 kg.m/s

Momentum for the ball moving towards the left side=mv=2.5*4=10 kg.m/s

Total momentum=-7.5 kg.m/s+10 kg.m/s=2.5 kg.m/s

5 0
3 years ago
An archer shoots an arrow 75 m distant target; the bull's-eye of the target is at the same height as the release height of the a
Liono4ka [1.6K]

Answer:

16.25^{\circ}

Explanation:

R = Horizontal range of projectile = 75 m

v = Velocity of projectile = 37 m/s

g = Acceleration due to gravity = 9.81\ \text{m/s}^2

Horizontal range is given by

R=\dfrac{v^2\sin2\theta}{g}\\\Rightarrow \theta=\dfrac{\sin^{-1}\dfrac{Rg}{v^2}}{2}\\\Rightarrow \theta=\dfrac{\sin^{-1}\dfrac{75\times 9.81}{37^2}}{2}\\\Rightarrow \theta=16.25^{\circ}

The angle at which the arrow is to be released is 16.25^{\circ}.

4 0
3 years ago
Why does a force perpendicular to an objects velocity change the direction of the velocity but not its magnitude
inna [77]

Answer:

According to your question although I think an object undergoing uniform circular motion is moving with a constant speed. Nevertheless, it is accelerating due to its change in direction. The direction of the acceleration is inwards,therefore a force perpendicular to an objects velocity change the direction of the velocity but not its magnitude.

3 0
3 years ago
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