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4 years ago

Which electrode (anode or cathode is designated as positive in an electrolytic cell?

1 answer:

4 0

Electrodes are part of an electrochemical cell that uses chemical reaction to produce energy,called voltaic cell. The electrode is defined with its flow of current, and according to this it is called a anode or cathode. Anode is designated as positive and attracts electrons (anions). On the other hand, the cathode is designated as negative and attracts positive charge (cations).

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A person pushes on the handle of a lawnmower with a force of 280. n. if the handle makes an angle of 40.0 degrees with the groun

Serggg [28]

<span>Force F = 280 N Angle with the ground = 40 degrees Weight of the Lawnmower = 350 N Velocity is constant so Acceleration is 0 So Forward force Ff = F cos theta = 280 cos40 Frictional force with resists to back Fb = (u x Force from pressure) + vertical component of Force, where u is the coefficient of friction. Fb = (u x m x g) + (u x 280sin40) AS Ff = Fb => 280 cos40 = u x ((m x g) + 280sin40) u = 280 cos40 / ((350 x 9.81) + 280sin40) = 214.49 / () = 0.405 So the coefficient of friction u = 0.405</span>

8 0

3 years ago

Read 2 more answers

the chef was careless and put the aluminum cookie sheet directly on the hot stove, which melted 0.05 kg of the aluminum. how muc

sergejj [24]

Heat required to melt 0.05 kg of aluminum is 28.7 kJ.

<h3>What is the energy required to melt 0.05 kg of aluminum?</h3>

The heat energy required to melt 0.05 kg of aluminum is obtained from the heat capacity of aluminum and the melting point of aluminum.

The formula to be used is given below:

Heat required = mass * heat capacity * temperature change

Assuming the aluminum sheet was at room temperature initially.;

Room temperature = 25 °C

Melting point of aluminum = 660.3 °C

Temperature difference = (660.3 - 25) = 635.3 903

Heat capacity of aluminum = 903 J/kg/903

Heat required = 0.05 * 903 * 635.3

Heat required = 28.7 kJ

In conclusion, the heat required is obtained from the heat change aluminum and the mass of the aluminum melted.

Learn more about heat capacity at: brainly.com/question/21406849

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3 0

2 years ago

A plane flying horizontally above earth’s surface at 100. meters per second drops a crate. the crate strikes the ground 30.0 sec

Lena [83]

Since the plane is traveling at 100m/s horizontal to the surface of the earth, the crate will always have this horizontal velocity (neglecting air resistance) until it hits the ground. So the answer is 100m/s. Note the vertical speed continues to change as the crate accelerates downward toward earth (again neglecting air effects)

3 0

3 years ago

Three strings, attached to the sides of a rectangular frame, are tied together by a knot as shown in the figure. The magnitude o

Anna [14]

The magnitude of the tension in the string marked A is 52.5N

Generally, the equation for is mathematically given as

Let's take θ be an angle at A

So, tanθ = 3/8

Let's take α be an angle at B (Below X)

tanα = 5/4

Let's take β be an angle at C (Below x)

tanβ = 1/6

First we take the Horizontal Components

74.9cos(9.46°) = Acos(20.6°) + Bcos(51.3°)

By solving the equation, we get

A = 78.9 - 0.668B … (1)

Now, we take the vertical components

74.9sin(9.46°) + Asin(20.6°) = Bsin(51.3°)

By solving the equation, we get

40.07 = 1.015B

B = 39.5N

By substituting the value of B in equation (1)

A = 78.9 - 0.6668× 39.5

A = 52.5N

Hence, the magnitude of the tension in the string marked A is 52.5N

Learn more about Tension here brainly.com/question/2287912

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8 0

2 years ago

A speaker fixed to a moving platform moves toward a wall, emitting a steady sound with a frequency of 235 Hz . A person on the p

Anvisha [2.4K]

Answer:

vr = 4.336 m/s

Explanation:

We are given that;

Beat frequency is 6Hz

Speed of sound = 344 m/s

Now,

Reflective Doppler frequency; f = 235 + 6 = 241 Hz

We can calculate the observed frequency if both the source sound and the observer are moving towards each other. In this case, the formula is:

f = fo[(c + vr)/(c + vs)]

Where;

ƒ = observed frequency

c = speed of sound

vs = velocity of source (negative if it’s moving toward the observer)

ƒ0 = emitted frequency of source

Since it’s moving toward the observer, thus we can rewrite equation as;

f = fo[(c + vr)/(c - vs)]

We have that;

fo = 235 , f = 241 , c = 344 , vr=vs

Thus,

241 = 235[(344+vr)/(344-vr)]

241(344 - vr)= 235(344 + vr)

82904 - 241vr = 80840 + 235vr

82904 - 80840 = 241vr + 235vr

2064 = 476 vr

vr = 2064/476

vr = 4.336 m/s

5 0

3 years ago