It depends how munch power your using with it. If flash is on it will tame more. Also brightness matter
The gravitational potential energy (GPE),is the energy of position given by GPE=mgh
Where m=mass in kilogram, g=acceleration due to gravity, h=height in meters
GPE=0.3×9.8×0.45=1.323J
Answer:
The total surface are of the bowl is given by: 0.0532*pi m² (approximately 0.166533 m²)
Explanation:
The total surface area of the semi-spherical bowl can be decomposed in three different sections: 1) an outer semi-sphere of radius 12 cm, 2) an inner semi-sphere of radius 10 cm, and 3) the edge, which is a 2-dimensional ring with internal radius of 10 cm and external radius of 12 cm. We will compute the areas independently and then sum them all.
a) Outer semi-sphere:
A1 = 2*pi*r² = 2*pi*(12 cm)² = 288*pi cm² = 904.78 cm²
b) Inner semi-sphere:
A2 = 2*pi*(10 cm)² = 200*pi cm² = 628.32 cm²
c) Edge (Ring):
A3 = pi*(r1² - r2²) = pi*((12 cm)²-(10 cm)²) = pi*(144-100) cm² = 44*pi cm² = 138.23 cm²
Therefore, the total surface area of the bowl is given by:
A = A1 + A2 + A3 = 288*pi cm² + 200*pi cm² + 44*pi cm² = 532*pi cm² (approximately 1665.33 cm²)
Changing units to m², as required in the problem, we get:
A = 532*pi cm² * (1 m² / 10, 000 cm²) = 0.0532*pi m² (approximately 0.166533 m²)
Answer:
-2.5m/s²
Explanation:
The acceleration of a body is giving by the rate of change of the body's velocity. It is given by
a = Δv / t ----------------(i)
Where;
a = acceleration (measured in m/s²)
Δv = change in velocity = final velocity - initial velocity (measure in m/s)
t = time taken for the change (measured in seconds(s))
From the question;
i. initial velocity = 5m/s
final velocity = 0 [since the body (ball) comes to rest]
Δv = 0 - 5 = -5m/s
ii. time taken = t = 2s
<em>Substitute these values into equation (i) as follows;</em>
a = (-5m/s) / (2s)
a = -2.5m/s²
Therefore, the acceleration of the ball is -2.5m/s²
NB: The negative sign shows that the ball was actually decelerating.
Answer:
1.13 x 10⁵N
Explanation:
Given parameters:
Pressure of the coin press = 3.2 x 10⁸ Pa
radius of the nickel coin = 0.0106m
Unknown:
Force of the press on coil = ?
Solution:
Our knowledge of pressure will help us solve this problem.
Pressure is defined as the force applied per unit area on a body.
Pressure = 
Force = Pressure x Area
Since the pressure is known;
Area of the coin = Area of a circle = π r²
where r is the radius of the coin;
Area of the coin = π x 0.0106² = 3.53 x 10⁻⁴m²
Force = 3.2 x 10⁸ x 3.53 x 10⁻⁴ = 1.13 x 10⁵N
