Question

Sample of pure boron contains only isotope X and isotope Y.

Answer 1

Answer:

I'm pretty sure the answer would be 17. just thinking wisely.

Answer 2

Answer:

$1.84$×$10^{-26}$

Explanation:

specific charge = $\frac{charge}{mass}$  so by rearranging for mass we get

mass= $\frac{charge}{sepcifc charge}$

$\frac{1.6×10^{-26} }{1.7×10^{-27} }$ = answer in kg