Phase 1. Forethought/preaction—This phase precedes the actual performance; sets the stage for action; maps out the tasks to minimize the unknown; and helps to develop a positive mindset. Realistic expectations can make the task more appealing. Goals must be set as specific outcomes, arranged in order from short-term to long-term. We have to ask students to consider the following:
<span>When will they start?Where will they do the work?How will they get started?<span>What conditions will help or hinder their learning activities are a part of this phase?
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Phase 2. Performance control—This phase involves processes during learning and the active attempt to utilize specific strategies to help a student become more successful.
We have to ask students to consider the following:
<span>Are students accomplishing what they hoped to do?Are they being distracted?Is this taking more time than they thought?Under what conditions do they accomplish the most?What questions can they ask themselves while they are working?<span>How can they encourage themselves to keep working (including self-talk—come on, get your work done so you can watch that television show or read your magazine!)
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Phase 3. Self-reflection—This phase involves reflection after the performance, a self-evaluation of outcomes compared to goals.
We have to ask students to consider the following:
<span>Did they accomplish what they planned to do?Were they distracted and how did they get back to work?Did they plan enough time or did they need more time than they thought?<span>Under what conditions did they accomplish the most work.
Hope this helps!!!!!
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Answer:
105 m/s
Explanation:
Given that the speed of train A,
= 45 m/s from west to east.
Speed of train B,
= 60 m/s from east to west.
Train B is moving in the opposite direction with respect to the speed of train A. Assuming that the speed from east to west direction is positive.
So, the speed of train A from east to west= - 45 m/s
The speed of train B w.r.t train A
m/s
Hence, the speed of train B w.r.t train A is 105 m/s from east to west.
The answer to this question would be:3850ft
To answer this question, you need to convert the speed velocity from miles/hour into feet/second. The equation would be: 750 miles/hour x 5280 foot/mile x 1 hour/3600second = 1100 ft/s
Then multiply the time with the velocity= 3.5 second x 1100 ft/s= 3850ft
Answer:
option D
Explanation:
given,
Intensity of sound = 20 dB
distance = 15 m
intensity of sound is increased to = 50 dB
distance between the sound level = ?
Using relation
![L_2 = L_1 - |20(log \dfrac{r_2}{r_1})|](https://tex.z-dn.net/?f=L_2%20%3D%20L_1%20-%20%7C20%28log%20%5Cdfrac%7Br_2%7D%7Br_1%7D%29%7C)
L₁ = 20 dB L₂ = 50 dB r₁ = 15 m r₂ = ?
![log (\dfrac{r_2}{r_1}) = \dfrac{L_1 -L_2}{20}](https://tex.z-dn.net/?f=log%20%28%5Cdfrac%7Br_2%7D%7Br_1%7D%29%20%3D%20%5Cdfrac%7BL_1%20-L_2%7D%7B20%7D)
![\dfrac{r_2}{r_1}= 10^{\dfrac{|L_1 -L_2|}{20}}](https://tex.z-dn.net/?f=%5Cdfrac%7Br_2%7D%7Br_1%7D%3D%2010%5E%7B%5Cdfrac%7B%7CL_1%20-L_2%7C%7D%7B20%7D%7D)
![r_2 =r_1 10^{\dfrac{|L_1 -L_2|}{20}}](https://tex.z-dn.net/?f=r_2%20%3Dr_1%2010%5E%7B%5Cdfrac%7B%7CL_1%20-L_2%7C%7D%7B20%7D%7D)
![r_2 =15 \times 10^{\dfrac{|20-50|}{20}}](https://tex.z-dn.net/?f=r_2%20%3D15%20%5Ctimes%2010%5E%7B%5Cdfrac%7B%7C20-50%7C%7D%7B20%7D%7D)
![r_2 =15 \times 10^{-1.5}](https://tex.z-dn.net/?f=r_2%20%3D15%20%5Ctimes%2010%5E%7B-1.5%7D)
r₂ = 0.47 m
r₂ = 47 cm
hence, the correct answer is option D