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kipiarov [429]
2 years ago
7

It is observed that in water the meniscus in the capillary tube is higher than the meniscus in the beaker,while in mercury the m

eniscus is lower than the meniscus in the beaker.explain these observations
Physics
1 answer:
coldgirl [10]2 years ago
6 0

Meniscus formed by water and mercury (In capillary tube and beaker):

Because the water wets the glass and seeps up the tube's side when it is contained in a glass tube, the meniscus (surface) of the water has a concave form. And in mercury, the meniscus is lower than the meniscus in the beaker because the intermolecular force between the mercury atom is stronger than the force within a wall of a container which is why mercury forms a lower meniscus.  

 

What are meniscus?:

The meniscus arises when the liquid and the container walls have different attractive forces acting on the molecules of the liquid.

A meniscus is created through adhesion, which is related to water's relatively high surface tension. The molecules in the glass beaker's wall are drawn to the water molecules. Whereas cohesion is the intermolecular attraction of similar molecules.

  • In water the meniscus in the capillary tube is higher than the meniscus in the beaker:  Because the glass pulls on the water molecules with a slightly stronger force than that which exists between the water molecules, the water and glass meniscus has a downward curvature. The glass's side is being dragged up with water.    
  • While in mercury the meniscus is lower than the meniscus in the beaker: Because the mercury atoms are more strongly attracted to one another than the glass is to the mercury atoms, thus it results in an upwardly curved meniscus.

Learn more about the meniscus here,

brainly.com/question/28009867

#SPJ4

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2 m

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The displacement of the ball will be the distance from the point of throwing to the ground i.e., 2 m as it is the shortest distance between the initial and final point of the ball's journey.

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3 years ago
The angular velocity of a process control motor is (13−12t2) rad/s, where t is in seconds. Part A At what time does the motor re
mihalych1998 [28]

Answer:

Explanation:

Given

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26=t^2

t=\sqrt{26}=5.099\approx 5.1 s

(b)

\frac{\mathrm{d} \theta }{\mathrm{d} t}=\omega

\int d\theta =\int_{0}^{5.1}\omega dt

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\theta =44.192^{\circ}

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The blades in a blender rotate at a rate of 6800 rpm . When the motor is turned off during operation, the blades slow to rest in
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**100 points** PLEASE ANSWER IN 3 PARAGRAPHS
Deffense [45]

Answer:

In the previous section, we defined circular motion. The simplest case of circular motion is uniform circular motion, where an object travels a circular path at a constant speed. Note that, unlike speed, the linear velocity of an object in circular motion is constantly changing because it is always changing direction. We know from kinematics that acceleration is a change in velocity, either in magnitude or in direction or both. Therefore, an object undergoing uniform circular motion is always accelerating, even though the magnitude of its velocity is constant.

You experience this acceleration yourself every time you ride in a car while it turns a corner. If you hold the steering wheel steady during the turn and move at a constant speed, you are executing uniform circular motion. What you notice is a feeling of sliding (or being flung, depending on the speed) away from the center of the turn. This isn’t an actual force that is acting on you—it only happens because your body wants to continue moving in a straight line (as per Newton’s first law) whereas the car is turning off this straight-line path. Inside the car it appears as if you are forced away from the center of the turn. This fictitious force is known as the centrifugal force. The sharper the curve and the greater your speed, the more noticeable this effect becomes.

Figure 6.7 shows an object moving in a circular path at constant speed. The direction of the instantaneous tangential velocity is shown at two points along the path. Acceleration is in the direction of the change in velocity; in this case it points roughly toward the center of rotation. (The center of rotation is at the center of the circular path). If we imagine Δs becoming smaller and smaller, then the acceleration would point exactly toward the center of rotation, but this case is hard to draw. We call the acceleration of an object moving in uniform circular motion the centripetal acceleration ac because centripetal means center seeking.

hope it helps! stay safe and tell me if im wrong pls :D

(brainliest if you want, or if its right pls) :)

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2 years ago
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