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kogti [31]
3 years ago
8

As an atom’s radius increases, 1. its ionization energy increases. 2. its ionizations energy increases or decreases depending on

whether you are going up a column or across a row. 3. its ionization energy does not change. 4. its ionization energy decreases
Physics
1 answer:
Serhud [2]3 years ago
5 0

Answer:

The correct option is: 4. its ionization energy decreases

Explanation:

Ionization energy refers to the energy required to pull a valence electron completely from the valence shell of a gaseous atom.

Now, in the <u>periodic table of chemical elements</u>, as we down a group, the atomic radius increases, so the effective nuclear charge experienced by the valence electron decreases. Therefore, the <u>ionization energy decreases</u><u>, down the group.</u>

As we across a period, the atomic radius usually decreases, so the effective nuclear charge experienced by the valence electron increases. Therefore, usually the <u>ionization energy increases</u><u>, across the period.</u>

<u>Therefore, as the atomic radius increases, the effective nuclear charge experienced by the valence electron decreases and thus the ionization energy also decreases.</u>

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Stels [109]

Answer:

A

Explanation:

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A 100-meter sprint is a race using only the straight side of a racetrack. A 400-meter sprint is a race that makes one complete l
Shalnov [3]
Speed uses distance and velocity uses displacement in its calculation.

For 100 m race, distance = displacement. Hence speed = velocity

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A bowling ball that has a radius of 11.0 cm and a mass of 5.00 kg rolls without slipping on a level lane at 2.80 rad/s.
NemiM [27]

Answer:

\dfrac{K_t}{K_r}=\dfrac{5}{2}

Explanation:

Given that,

Mass of the bowling ball, m = 5 kg

Radius of the ball, r = 11 cm = 0.11 m

Angular velocity with which the ball rolls, \omega=2.8\ rad/s

To find,

The ratio of the translational kinetic energy to the rotational kinetic energy of the bowling ball.

Solution,

The translational kinetic energy of the ball is :

K_t=\dfrac{1}{2}mv^2

K_t=\dfrac{1}{2}m(r\omega)^2

K_t=\dfrac{1}{2}\times 5\times (0.11\times 2.8)^2

The rotational kinetic energy of the ball is :

K_r=\dfrac{1}{2}I \omega^2

K_r=\dfrac{1}{2}\times \dfrac{2}{5}mr^2\times \omega^2

K_r=\dfrac{1}{2}\times \dfrac{2}{5}\times 5\times (0.11)^2\times (2.8)^2

Ratio of translational to the rotational kinetic energy as :

\dfrac{K_t}{K_r}=\dfrac{5}{2}

So, the ratio of the translational kinetic energy to the rotational kinetic energy of the bowling ball is 5:2

4 0
3 years ago
A car travelling 95 km/h is 210 behind a truck travelling 75 km/h. how long will it take the care to reach the truck
masya89 [10]
<span>37.8 seconds First, determine the speed difference between the car and truck. 95 km/h - 75 km/h = 20 km/h Convert that speed into m/s to make a more convenient unit of measure. 20 km/h * 1000 m/km / 3600 s/h = 5.556 m/s Now it's simply a matter of dividing the distance between the two vehicles and their relative speed. 210 m / 5.556 m/s = 37.8 s So it will take 37.8 seconds for the car to catch the truck that's 210 meters in front of the car.</span>
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You kick a soccer ball across a field the ball travels across the field and slowly comes to a stop. Since the ball slowly comes
marysya [2.9K]

Answer:

It slowly decreases and the friction acting on it slowing it down becomes the bigger net force, if that makes sense :)

Explanation:

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