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kogti [31]
3 years ago
8

As an atom’s radius increases, 1. its ionization energy increases. 2. its ionizations energy increases or decreases depending on

whether you are going up a column or across a row. 3. its ionization energy does not change. 4. its ionization energy decreases
Physics
1 answer:
Serhud [2]3 years ago
5 0

Answer:

The correct option is: 4. its ionization energy decreases

Explanation:

Ionization energy refers to the energy required to pull a valence electron completely from the valence shell of a gaseous atom.

Now, in the <u>periodic table of chemical elements</u>, as we down a group, the atomic radius increases, so the effective nuclear charge experienced by the valence electron decreases. Therefore, the <u>ionization energy decreases</u><u>, down the group.</u>

As we across a period, the atomic radius usually decreases, so the effective nuclear charge experienced by the valence electron increases. Therefore, usually the <u>ionization energy increases</u><u>, across the period.</u>

<u>Therefore, as the atomic radius increases, the effective nuclear charge experienced by the valence electron decreases and thus the ionization energy also decreases.</u>

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It requires 350 joules to raise a certain amount of a substance from 10.0°C to 30.0°C. The specific heat of the substance is 1.2
Akimi4 [234]
I'll assume you are looking for the mass of the object, since that is the missing piece of the puzzle.

The important equation for heat and energy is

Energy = mass × specific heat × change in temperature

Things we know:
Energy needed is 350 J.
Specific heat = 1.2 J/g°C
Temp. change = (30-20)°

Now we just need to plug those in and rearrange the formula to find the mass!

350 = mass × 1.2 × 10
6 0
4 years ago
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Two billiard balls move toward each other on a table. The mass of the number three ball, m1, is 5 g with a velocity of 3 m/s. Th
Stels [109]

This question deals with the law of conservation of momentum, which basically says that the total momentum in a system must stay the same, provided there are no outside forces. Since you were given the mass and velocity of the two objects you can find the momentum (p=mv) of each and then add them together to find the total momentum of the system before they collide. This total momentum must be the same after they collide.  Since you have the mass and velocity of one of the objects after the collision you can find the its momentum after.  Subtract this from the the system total and you will have the momentum of the other object after the collision.  Now that you know the momentum of the other object you can find its velocity using p=mv and its mass from before.

Be careful with the velocities.  They are vectors, so direction matters.  Typically moving to the right is positive (+) and moving to the left is negative (-).  It is not clear from your question which direction the objects are moving before and after the collision.

6 0
3 years ago
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What is the force on a person’s hand, which is using a rope to accelerate a 5 kg block upward with an acceleration of 2.2 m/s 2
slavikrds [6]

Answer:

F = 11 N

Explanation:

Given,

Mass of a block, m = 5 kg

Acceleration of the block, a = 2.2 m/s²

We need to find the force on the person's hand. Let it is F. We know that force is given by the product of mass and acceleration as follows :

F = ma

F = 5 kg × 2.2 m/s²

F = 11 N

So, the force on a person's hand is 11 N.

5 0
3 years ago
How much energy does the light bulb dissipate in 1 minmin when half that voltage is supplied? Express your answer in kilojoules
natali 33 [55]

Answer:

E = 15 P₀

Explanation:

The power dissipated in a light bulb is

       P = V I

       V = I R

       P = V² / R

the power is defined by

       P = W / t

work equals energy

       P = E / t

we substitute

       V² / R = E / t

        E = V² t / R

let's reduce the time to SI units

         t = 1 min = 60 s

let's calculate the dissipated energy

     

In the exercise it does not indicate the nominal voltage of the bulb, but in general this voltage is V₀= 120 V

         

The applied voltage is half the nominal voltage

      V = V₀ / 2

      V = 120/2 = 60 V

       

       E = (V₀ / 2)² t / R

       E = ¼ t   V₀² / R

       E = ¼ 60 P₀

       E = 15 P₀

Many times the nominal power (P₀) is written on the box of the bulb

4 0
3 years ago
Which statement does not support the explanation for how planets formed by accretion of particles?
navik [9.2K]
It has to be the second answer
7 0
4 years ago
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