Answer:
elements in the same column have the same number of neutrons. elements with similar mass are placed in the same column.
T<span>he equation to be used here to determine the distance between two equipotential points is:
V = k * Q / r
where v is the voltage of the point, k is a constant, Q is charge of the point measured in coloumbs and r is the distance.
In this case, we can use ratio of proportions to determine the distance between the two points. in this respect,
Point 1:
V = k * Q / r = 290
r = k*Q/290 ; kQ = 290r
Point 2:
V = k * Q / R = 41
R = k*Q/41
from equation 10 kQ = 290r
R = 290/(41)= 7.07 m
The distance between the two points then is equal to 7.07 m.
</span>
<u>Communications:</u> Laura develops programs that flag suspicious network activity.
<h3>What is
communication?</h3>
Communication involves the transfer of information from one person (sender) to another (recipient), especially through the use of semiotics, symbols, signs and network devices.
<h3>How to match the scenarios?</h3>
- <u>Communications:</u> Laura develops programs that flag suspicious network activity.
- <u>Healthcare:</u> Greg calibrates electronic scales.
- <u>Manufacturing:</u> Tim ensures the output of a process remains in a defined range.
Read more on communication here: brainly.com/question/26152499
#SPJ1
First, let's express the movement of Car A and B in terms of their position over time (relative to car B)
For car A: y=20x-200 Car A moves 20 meters every second x, and starts 200 meters behind car B
For Car B: y= 15x Car B moves 15 meters every second and starts at our basis point
Set the two equations equal to one another to find the time x at which they meet:
20x - 200 = 15x
200 = 5x
x= 40
At time x=40 seconds, the cars meet. How far will Car A have traveled at this time?
Car A moves 20 meters every second:
20 x 40 = 800 meters
