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Mademuasel [1]
2 years ago
12

Imagine that our Sun were magically and suddenly replaced by a black hole of the same mass (1 solar mass). How would Earth's orb

it change
Physics
1 answer:
aleksandrvk [35]2 years ago
7 0

There is no effect on earth's orbit due to similar force of gravity of black hole.

<h3> How would Earth's orbit change?</h3>

If our Sun was replaced with a black hole having the same mass, Earth's orbit will not changed because of the same force of gravitation of balck hole on earth. Due to this replacement, Earth's temperature will change because balck hole is not too hot like sun.

So we can conclude that there is no effect on earth's orbit due to similar force of gravity of black hole.

Learn more about sun here: brainly.com/question/15837114

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A wind turbine is rotating counterclockwise at 0.626 rev/s and slows to a stop in 12.9 s. Its blades are 17.9 m in length. What
iogann1982 [59]

Answer:

276.5 m/s^2

Explanation:

The initial angular velocity of the turbine is

\omega=0.626 rev/s \cdot 2\pi rad/rev =3.93 rad/s

The length of the blade is

r = 17.9 m

So the centripetal acceleration is given by

a=\omega^2 r

At the instant t = 0,

\omega=3.93 rad/s

So the centripetal acceleration of the tip of the blades is

a=(3.93 rad/s)^2 (17.9 m)=276.5 m/s^2

5 0
2 years ago
What was significant about the discovery of gallium
Kryger [21]
It confirmed medeleeve's hypothesis (prediction) and showed the use of his table
8 0
3 years ago
Read 2 more answers
What does the negative sign in F = –kx mean?
Andru [333]
The force is opposite to the displacement
3 0
3 years ago
Mechanical energy often changes between potential and kinetic energy. True or False
Allushta [10]

I wanna say its ture but it didnt exactly say that is transfered from those types of energy so I would just say false

8 0
3 years ago
Read 2 more answers
. A bathysphere used for deep-sea exploration has a radius of 1.50 m and a mass of 1.20 104 kg. To dive, this submarine takes on
dangina [55]

Answer:

Explanation:

Given that,

Bathysphere radius

r = 1.5m

Mass of bathysphere

M = 1.2 × 10⁴ kg

Constant speed of descending.

v = 1.2m/s

Resistive force

Fr = 1100N upward direction

Density of water

ρ = 1.03 × 10³kg/m³

The volume of the bathysphere can be calculated using

V = 4πr³ / 3

V = 4π × 1.5³ / 3

V = 14.14 m³

The Bouyant force can be calculated using

Fb = ρgV

Fb = 1.03 × 10³ × 9.81 × 14.14

Fb = 142,846.18 N

Buoyant force is acting upward

Weight of the bathysphere

W = mg

W = 1.2 × 10⁴ × 9.81

W = 117,720 N

Weight is acting downward

The net positive buoyant using resolving

Fb+ = Fb — W

Fb+ = 142,846.18 — 117,720

Fb+ = 25,126.18 N

The force acting downward is the weight of the submarine and it is equal to the positive buoyant force and the resistive force

W = Fb+ + Fr

W = 25,126.18 + 1100

W = 26,226.18

mg = 26,226.18

m = 26,226.18 / 9.81

m = 2673.4kg

Mass of submarine is 2673.4kg

8 0
3 years ago
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