Answer:
Work- Activity involving mental or physical effort done in order to achieve a purpose or result.
Explanation:
This was the first definition from the dictionary on google :)
Answer:
8977.7 kg/m^3
Explanation:
Volume of water displaced = 55 cm^3 = 55 x 10^-6 m^3
Reading of balance when block is immersed in water = 4.3 N
According to the Archimedes principle, when a body is immersed n a liquid partly or wholly, then there is a loss in the weight of body which is called upthrust or buoyant force. this buoyant force is equal to the weight of liquid displaced by the body.
Buoyant force = weight of the water displaced by the block
Buoyant force = Volume of water displaced x density of water x g
= 55 x 10^-6 x 1000 x .8 = 0.539 N
True weight of the body = Weight of body in water + buoyant force
m g = 4.3 + 0.539 = 4.839
m = 0.4937 kg
Density of block = mass of block / volume of block
= ![\frac{0.4937}{55\times10^{-6}}](https://tex.z-dn.net/?f=%5Cfrac%7B0.4937%7D%7B55%5Ctimes10%5E%7B-6%7D%7D)
Density of block = 8977.7 kg/m^3
Answer:
1.122 m/s
Explanation:
So usually a river with a speed of 1 meters per second can transport particle that weighs:
![1^6 = 1 kg](https://tex.z-dn.net/?f=%201%5E6%20%3D%201%20kg)
If the particle is twice as massive as usual, then its weights would be 1 * 2 = 2kg
This means the river must be flowing at a speed of
![2^{\frac{1}{6}} = 1.122 m/s](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B1%7D%7B6%7D%7D%20%3D%201.122%20m%2Fs)
Answer:
71.19 C
Explanation:
25C = 25 + 273 = 298 K
Applying the ideal gas equation we have
![\frac{P_1V_1}{T_1} = \frac{P_2V_2}{T_2}](https://tex.z-dn.net/?f=%5Cfrac%7BP_1V_1%7D%7BT_1%7D%20%3D%20%5Cfrac%7BP_2V_2%7D%7BT_2%7D)
where P, V and T are the pressure, volume and temperature of the gas at 1st and 2nd stage, respectively. We can solve for the temperature and the 2nd stage:
![T_2 = T_1\frac{P_2V_2}{P_1V_1} = 298\frac{0.77*1.8}{1.2*1} = 298*1.155 = 344.19 K = 344.19 - 273 = 71.19 C](https://tex.z-dn.net/?f=T_2%20%3D%20T_1%5Cfrac%7BP_2V_2%7D%7BP_1V_1%7D%20%3D%20298%5Cfrac%7B0.77%2A1.8%7D%7B1.2%2A1%7D%20%3D%20298%2A1.155%20%3D%20344.19%20K%20%3D%20344.19%20-%20273%20%3D%2071.19%20C)
Answer : The final temperature is, ![25.0^oC](https://tex.z-dn.net/?f=25.0%5EoC)
Explanation :
In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.
![q_1=-q_2](https://tex.z-dn.net/?f=q_1%3D-q_2)
![m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)](https://tex.z-dn.net/?f=m_1%5Ctimes%20c_1%5Ctimes%20%28T_f-T_1%29%3D-m_2%5Ctimes%20c_2%5Ctimes%20%28T_f-T_2%29)
where,
= specific heat of ice = ![2.09J/g^oC](https://tex.z-dn.net/?f=2.09J%2Fg%5EoC)
= specific heat of water = ![4.18J/g^oC](https://tex.z-dn.net/?f=4.18J%2Fg%5EoC)
= mass of ice = 50 g
= mass of water = 200 g
= final temperature = ?
= initial temperature of ice = ![-15^oC](https://tex.z-dn.net/?f=-15%5EoC)
= initial temperature of water = ![30^oC](https://tex.z-dn.net/?f=30%5EoC)
Now put all the given values in the above formula, we get:
![50g\times 2.09J/g^oC\times (T_f-(-15))^oC=-200g\times 4.184J/g^oC\times (T_f-30)^oC](https://tex.z-dn.net/?f=50g%5Ctimes%202.09J%2Fg%5EoC%5Ctimes%20%28T_f-%28-15%29%29%5EoC%3D-200g%5Ctimes%204.184J%2Fg%5EoC%5Ctimes%20%28T_f-30%29%5EoC)
![T_f=25.0^oC](https://tex.z-dn.net/?f=T_f%3D25.0%5EoC)
Therefore, the final temperature is, ![25.0^oC](https://tex.z-dn.net/?f=25.0%5EoC)