1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
makvit [3.9K]
3 years ago
11

On your business card , you position your businesses as "the area's most creative cookery " this phrase is your

Physics
1 answer:
klasskru [66]3 years ago
8 0
It would be Slogan ;)

You might be interested in
How are mixtures and pure substances related?
Elden [556K]
You are talking about make sure's and pearl substance I thought you was talking about mix in with something
4 0
3 years ago
In a game of angry birds you launch a bird with an angle of 53 degrees to horizontal. Unfortunatly, its not a good shot and the
Alisiya [41]

Answer:

The maximum height covered is 3.25 m.

The horizontal distance covered is 9.81 m.

The total time in the air is 1.63 seconds.

Explanation:

The launch speed, u_0= 10 m/s.

Angle of launch with the horizontal, \theta = 53 ^{\circ}

So, the vertical component of the initial velocity,

u_0\sin\theta=10 \sin 53 ^{\circ}\cdots(i).

The horizontal component of the initial velocity,

u_0\cos\theta=10 \cos 53 ^{\circ}

Let, t be the time of flight, to the horizontal distance covered

D=10 \cos (53 ^{\circ})t\cdots(ii).

Not, applying the equation of motion in the vertical direction.

s= ut +\frac 1 2 at^2

Where s is the displacement in time t, u is the initial velocity and a is the acceleration.

In this case, u =10 \sin 53 ^{\circ} (from equation (i), s=0 (as the final height is same as the launch height) and a = -9.81 m/s^2 (negative sign is due to the downward direction).

\Rightarrow 0 = 10 (\sin 53 ^{\circ})t-\frac 1 2 (9.81)t^2

\Rightarrow t= \frac {2\times 10 (\sin 53 ^{\circ})}{9.81}=1.63 seconds.

So, the total time in the air is 1.63 seconds.

From equation (i),

Total horizontal distance covered is

D=10 \cos (53 ^{\circ})\times 1.63 = 9.81 m.

Now, for the maximum height, H, applying the equation of motion as

v^2=u^2+2as

Here, v is the final velocity and v=0 (at the maximum height), and h=H.

So, 0^2=(10 \sin 53 ^{\circ})^2-2(9.81)H

\Rightarrow H = \frac {(10 \sin 53 ^{\circ})^2}{2\times 9.81}

\Rightarrow H = 3.25 m.

Hence, the maximum height covered is 3.25 m.

8 0
3 years ago
4. What are 3 things that you can think of doing, that would reduce<br> your electricity bill?
Cloud [144]
Turn off standby appliances.
Install a smart thermostat.
Turn down your thermostat.
Buy efficient appliances.
Install a new boiler.
Wash clothes at a lower temperature.
Be smarter about water.
Invest in double glazing.
3 0
3 years ago
Do you want robot referees in your favorite class?
jeka94

Answer:

Sounds cool.. but what do they do?

Explanation:

5 0
3 years ago
Read 2 more answers
University Physics 9.68: Accelerating Compact Disc. A computer disc drive is turned on starting from rest and has constant angul
faust18 [17]

Hey! How are you? My name is Maria, 19 years old. Yesterday broke up with a guy, looking for casual sex.

Write me here and I will give you my phone number - *pofsex.com*

My nickname - Lovely

5 0
3 years ago
Other questions:
  • What is the direction of transfer of energy in the waves produced?
    15·2 answers
  • Please help me asapp!!!!!!!!!!!!!!!!
    10·2 answers
  • An element has three stable isotopes. One has a mass number of 63 and an abundance of 50%. The second has a mass number of 65 an
    15·1 answer
  • A block is projected up a frictionless inclined plane with initial speed v0 = 1.72 m/s. The angle of incline is θ = 44.8°. (a) H
    6·1 answer
  • Mechanics is the study of
    7·1 answer
  • A 2.0 kg particle moves in a circle of radius 3.1 m. As you look down on the plane of its orbit, the particle is initially movin
    5·2 answers
  • 40 POINTS!!! + BRAINLIEST!!!
    11·1 answer
  • Work and power!!
    15·1 answer
  • In a PE class, the teacher requires his students to monitor periodically their progress towards the fitness goals. Which of thes
    11·1 answer
  • Question 9 of 10
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!