L = 4 + w
perimeter = 38
38 = w + 4 + w
2w = 34
w = 17
L = 4 + 17
L = 21
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Answer:
Suppose a population of rodents satisfies the differential equation dP 2 kP dt = . Initially there are P (0 2 ) = rodents, and their number is increasing at the rate of 1 dP dt = rodent per month when there are P = 10 rodents.
How long will it take for this population to grow to a hundred rodents? To a thousand rodents?
Step-by-step explanation:
Use the initial condition when dp/dt = 1, p = 10 to get k;
Seperate the differential equation and solve for the constant C.
You have 100 rodents when:
You have 1000 rodents when:
Answer:
Step-by-step explanation:
The equation for that is
If we subtract over the 70, we have a quadratic that we can factor to solve for the values of x that will make that equation true.
Now we need the factors of 70 that will either add or subtract to give us the linear term of 3. The factors of 70 that will work are 10 and 7. 10 times 7 is 70, and 10 - 7 = 3:
and now we will factor by grouping:
and factor out what's common:
The factor (x + 10) is common, so we will now factor that out:
By the Zero Product Property, either x + 10 = 0 or x - 7 = 0, so x = -10 or 7
Those are the 2 numbers that will work.
simplifies to
100 - 30 which does in fact equal 70. OR
which simplifies to
49 + 21 which also equals 70.
So you're done!
Answer:
Step-by-step explanation:
If that is a square, then all sides are the same. Therefore, it's a by shape. We'll use Pythagorean Theorem to find the diagonal.
Since it's not a fraction, there is no denominator to rationalize. Let me know if you have any other questions!
Answer: 2.95x+39.95(12)
Step-by-step explanation:
Hi, to answer this question we have t write an expression with the information given:
The yearly cost for x movie rentals is equal to : the product of the cost of each movie (2.95) and the number of movies (x) ;plus the product of the monthly fee (39.95) and the number of months in a year (12)
Mathematically speaking:
2.95x+39.95(12)