Answer:
430;400
Step-by-step explanation:
So tenth is the 2.. 5 makes it go to 3 430
hundred we look to change 4 so we look at tenths 2 is less than 5 so it stays the same 400
The answer is log3 k to the seventh power m to the sixth power over n to the ninth power
a * logₓ(y) = logₓ(yᵃ)
7 log₃ (k) = log₃ (k⁷)
6 log₃ (m) = log₃ (m⁶)
9 log₃ (n) = log₃ (n⁹)
7 log₃ (k) + 6 log₃ (m) - 9 log₃ (n) = log₃ (k⁷) + log₃ (m⁶) - log₃ (n⁹)
logₓ(y) + logₓ(z) = logₓ(y * z)
log₃ (k⁷) + log₃ (m⁶) - log₃ (n⁹) = log₃ (k⁷ * m⁶) - log₃ (n⁹)
logₓ(y) - logₓ(z) = logₓ(y / z)
log₃ (k⁷ * m⁶) - log₃ (n⁹) = log₃ (k⁷ * m⁶ / n⁹)
Let after n week both tanks have same quantity of water .
for first tank
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tank hold 540 gallon of water ,
leaking of water 4 gallon /week
so, in n week water leak from the tank =4× n = 4n
now, after n week quantity of water in the tank = 540 -4n
for second tank
==============
quantity of water in the tank =720 gallon
leaking of water at the rate = 7gallon/week
so, after n week water leak from the tank = 7× n =7n
after n week quantity of water rest in the tank = 720 -7n
now ,
according to question ,
water in first tank = water in second tank
540 -4n = 720 -7n
7n -4n = 720 -540
3n = 180
n = 60
hence , after 60 week both tank have same quantity of water.
40000=5000e^30r
40000/5000=e^30r
R=(log(40000/5000)/log(e))/30)*100
R=6.93%
