525 feet above the ground
Answer: D) cube root of 16
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Explanation:
The rule we use is
![x^{m/n} = \sqrt[n]{x^m}](https://tex.z-dn.net/?f=x%5E%7Bm%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D)
In this case, x = 4, m = 2 and n = 3.
So,
![x^{m/n} = \sqrt[n]{x^m}\\\\\\4^{2/3} = \sqrt[3]{4^2}\\\\\\4^{2/3} = \sqrt[3]{16}\\\\\\](https://tex.z-dn.net/?f=x%5E%7Bm%2Fn%7D%20%3D%20%5Csqrt%5Bn%5D%7Bx%5Em%7D%5C%5C%5C%5C%5C%5C4%5E%7B2%2F3%7D%20%3D%20%5Csqrt%5B3%5D%7B4%5E2%7D%5C%5C%5C%5C%5C%5C4%5E%7B2%2F3%7D%20%3D%20%5Csqrt%5B3%5D%7B16%7D%5C%5C%5C%5C%5C%5C)
Showing that the original expression turns into the cube root of 16.
Answer:
um i don't know this (i do im just lazy as heck)
Step-by-step explanation:
Answer:
X intercept: (7/2, 0)
Y intercept: (0, -7/3)
Step-by-step explanation: Add 7 to both sides. We get 2x-3y=7
Now, plug in zero for y, and we are left with 2x = 7 (the y cancels.) Dividing by 2 leaves us 7/2, and (0, 7/2)
Now starting back to 2x-3y=7
Plug in zero for x, and we are legt with -3y = 7 (the x cancels.) Divide by -3, and we get -7/3 and (-7/3, 0)
Answer:
The number of different 7 card hands possibility is 133784560
Step-by-step explanation:
The computation of the number of different 7 card hands possibility is shown below:
Here we use the combination as the orders of choosing it is not significant
So,
The number of the different hands possible would be
= 
= 52! ÷ (7! × (52 - 7)!)
= 133784560
Hence, the number of different 7 card hands possibility is 133784560