Since BE bisects angle ABC, you know that angles ABE and EBC are congruent and have the same measure. This means
2x + 20 = 4x - 6
Solve for x:
(2x + 20) - 2x + 6 = (4x - 6) - 2x + 6
26 = 2x
26/2 = 2x/2
13 = x
Then angle ABE has measure 2*13 + 20 = 46º.
The better deal is the 200 calculators
Answer:
a) 166x.
Step-by-step explanation:
167x - x
= 166x.
Answer:
<u>Given:</u>
- DC ║ AB
- CM = MB as M is midpoint of BC
i) <u>Since DN and BC are transversals, we have:</u>
- ∠DCM ≅ ∠NBM and
- ∠CDM ≅ ∠BNM as alternate interior angles
<u>As two angles and one side is congruent, the triangles are also congruent:</u>
- ΔDCM ≅ ΔNBM (according to AAC postulate)
So their areas are same.
ii)
<u>The quadrilateral has area of:</u>
- A(ADCB) = A(ADMB) + A(DCM)
<u>And the triangle has area of:</u>
- A(ADN) = A(ADMB) + A(NBM)
Since the areas of triangles DCM and NBM are same, the quadrilateral ADCB has same area as triangle ADN.
Answer:
81 times the original size
Step-by-step explanation:
AA0ktA=3A0=?=?=25hours=A0ekt
Substitute the values in the formula.
3A0=A0ek⋅25
Solve for k. Divide each side by A0.
3A0A0=e25k
Take the natural log of each side.
ln3=lne25k
Use the power property.
ln3=25klne
Simplify.
ln3=25k
Divide each side by 25.
ln325=k
Approximate the answer.
k≈0.044
We use this rate of growth to predict the number of bacteria there will be in 100 hours.
AA0ktA=3A0=?=ln325=100hours=A0ekt
Substitute in the values.
A=A0eln325⋅100
Evaluate.
A=81A0
At this rate of growth, we can expect the population to be 81 times as large as the original population.