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poizon [28]
3 years ago
12

Element X reacts with chlorine to form an ionic compound that has a formula of XCl2. To which group could element X belong?(1) G

roup 1 (2) Group 2 (3) Group 13 (4) Group 15
Chemistry
2 answers:
kap26 [50]3 years ago
7 0
Chlorine has a charge -1. It means that X is +2 so that the formula is XCl2. Group 2 is the correct answer.
Neporo4naja [7]3 years ago
6 0

Answer;

Group 2

Explanation;

-Elements in group 2 (alkaline earth metals) have a 2 valence electrons (two electrons in the outermost energy shell). Which means that for these elements to achieve an octet configuration, they will have to loose two electrons. Therefore; element X has a valency electrons, it reacts chlorine to form a compound (XCl2), since chlorine has a valency of 1.

You might be interested in
give a general description of the location of metals , non metals and metalloids on the periodic table
zheka24 [161]

Answer:

Metals at the top

nonmetals at the bottom

metalloids in the middle

Don't quote me, i could be wrong. i think this is the correct order.

Explanation:

7 0
3 years ago
1. How much heat (in calories) is needed to raise 20 g of H2O from 5°C to 40°C? (c = 1.0 cal/g °C)
KIM [24]

Answer:

700 calories

Explanation:

Using the formula below:

Q = m × c × ∆T

Where;

Q = amount of heat required (calories)

m = mass of substance (g)

c = specific heat of substance (cal/g°C)

∆T = change in temperature (°C)

According to this question, the following information was provided;

Q = ?

m = 20g

c = 1.0 cal/g °C

∆T = 40°C - 5°C = 35°C

Using the formula; Q = m × c × ∆T

Q = 20 × 1 × 35

Q = 700 calories

Hence, 700 cal of heat energy is needed to raise 20 g of H2O from 5°C to 40°C.

6 0
3 years ago
How many moles of oxygen are necessary to generate 28 moles of water, according to the following equation: 2H2+O2→2H2O
valentinak56 [21]

The number of moles of oxygen required to generate 28 moles of water from the reaction is 14 moles

<h3>Balanced equation </h3>

2H₂ + O₂ —> 2H₂O

From the balanced equation above,

2 moles of water were obtained from 1 mole of oxygen

<h3>How to determine the mole of oxygen needed </h3>

From the balanced equation above,

2 moles of water were obtained from 1 mole of oxygen

Therefore,

28 moles of water will be obtained from = 28 / 2 = 14 moles of oxygen

Thus, 14 moles of oxygen are needed for the reaction

Learn more about stoichiometry:

brainly.com/question/14735801

5 0
2 years ago
What is the value for the reaction: N2(g) + 2 O2(g) --&gt; N2O4(g) in terms of K values from the reactions:
Valentin [98]

Answer : The correct expression will be:

K=(K_1)^2\times K_2

Explanation :

The chemical reactions are :

(1) \frac{1}{2}N_2(g)+\frac{1}{2}O_2(g)\rightleftharpoons NO(g) K_1

(2) 2NO(g)+O_2(g)\rightleftharpoons N_2O_4(g) K_2

The final chemical reaction is :

N_2(g)+2O_2(g)\rightleftharpoons N_2O_4 K=?

Now we have to calculate the value of K for the final reaction.

Now equation 1 is multiply by 2 and then add both the reaction we get the value of 'K'.

If the equation is multiplied by a factor of '2', the equilibrium constant will be the square of the equilibrium constant of initial reaction.

If the two equations are added then equilibrium constant will be multiplied.

Thus, the value of 'K' will be:

K=(K_1)^2\times K_2

6 0
3 years ago
A student pours 800.0 mL of a 3.000 molar solution of sodium hydroxide into a 2.00 liter volumetric flask and fills the flask up
hammer [34]
M1V1 = M2V2
M1 = 3.000 M
V1 = 0.8000 L
M2 = ?
V2 = 2.00 L

M2 = M1V1/V2 = (3.000 M)(0.8000 L)/(2.00 L) = 1.20 M
5 0
3 years ago
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