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ad-work [718]
3 years ago
15

What colour is litmus in a solution of pH 4?

Chemistry
1 answer:
schepotkina [342]3 years ago
6 0

Answer:

in solution of PH4 it is red

in water it is blue

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Calculate the mass of solid sodium that's needed to fully react with 4.0 L of chlorine gas at STP.
aalyn [17]

Answer: 8.28g Na

Explanation: use ideal gas law

PV= nRT

Solve for moles of Cl2

n= PV/ RT

Substitute:

= 1 atm x 4.0 L / 0.08205 L.atm/ mol. K x 273 K

= 0.18 moles Cl2

Do stoichiometry to solve for m of Na

2 Na + Cl2 => 2 NaCl2

=0.18 moles Cl2 x 2 mol Na/ 1 mol Cl2 x 23g Na / 1 mol Na

= 8.28 g Na.

5 0
3 years ago
The following equation shows the correct molecules formed in the reaction, but the products are incorrect. CH4 +202=H20+ CO2 How
Hunter-Best [27]
For the equation to balance out, you would need 2 H2O on the product. That will give a total of 1 Carbon, 4 Hydrogens and 4 Oxygens on each side.
5 0
4 years ago
What is the difference between Mixtures and Compounds? I am trying to study for my Science quiz on Tuesday, and I need to know t
Deffense [45]
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8 0
3 years ago
Why is it that you can not feel earths movement but you can observes its effects
ss7ja [257]
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5 0
3 years ago
How many grams of Pb are contained in a mixture of 0.135 kg each of PbCl(OH) and Pb2Cl2CO3?
Dahasolnce [82]

Hey there!:

Given the mass of PbCl(OH) :

0.135 Kg = 0.135 Kg*(1000g / 1Kg)  = 135 g

Molecular mass of PbCl(OH)  = 207+35.5+16+1  = 259.5 g / mol

Atomic mass of Pb = 207 g/mol

Hence mass of Pb in 135 g  PbCl(OH)  :

(207 g Pb /  259.5 g PbClOH) * 135g PbClOH  =

0.79768 * 135 =>  107.68 g of Pb

For Pb2Cl2CO3  :

Given the mass of Pb2Cl2CO3  :

0.135 Kg = 0.135 Kgx(1000g / 1Kg)  = 135 g

Molecular mass of Pb2Cl2CO3  = 2*207+2*35.5+12+3*16  = 545 g / mol

Mass of Pb present in 1 mol (=545 g / mol) of Pb2Cl2CO3  = 2*207 = 414 g

Hence mass of Pb in 135 g  Pb2Cl2CO3:

(414 g Pb /  545 g PbClOH) * 135g PbClOH  =

0.75963 * 135 => 102.55 g of Pb2Cl2CO3


Hope that helps!

8 0
3 years ago
Read 2 more answers
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