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Annette [7]
3 years ago
14

Calcium acetate is added to sodium carbonate

Chemistry
1 answer:
sattari [20]3 years ago
3 0
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This dipeptide is designated as: there is a structure for h3nchcnhchco with ch2oh group attached to the first (from left to righ
oksian1 [2.3K]

A dipeptide is formed when 2 amino acids are joined together by a peptide linkage.

Each amino acid molecule contains an amino group ( -NH₂) and a carboxyl ( -COOH) group. During peptide formation, a carboxyl group of one amino acid reacts with amino group of the other , resulting in the formation of a linkage known as "peptide linkage". A water molecule is also eliminated in this reaction.

A general peptide formation reaction can be written as

NH_{2}-CH_{2}-COOH + H_{2}N-CH_{2}-COOH \rightarrow NH_{2}-CH_{2}-CONH-CH_{2}-COOH +H_{2}O

In the above reaction, we can see a peptide linkage ( -CONH-) getting formed between 2 amino acid molecules.

In the given molecule the peptide linkage is shown by drawing a box around it. Please refer to the attached image.

If we want to know the amino acid molecules from which this peptide is formed, we will simply break the CO-NH bond.

We will add -OH group to CO part and -H to NH part to get 2 amino acid molecules as shown in the picture.

The two amino acids thus formed are Serine & Cysteine.

Serine is designated as "Ser" and Cysteine is designated as "Cys"

Therefore the given dipeptide is designated as "Ser-Cys"

4 0
3 years ago
What objects in the solar system are larger
GalinKa [24]

Answer:

d

Explanation:

the outer planets are uranus neptune jupiter and saturn also the sun all way bigger than the earth

6 0
1 year ago
(c) O2 gas is transferred from a 3 L vessel containing oxygen at 4 atm to an evacuated 20 L vessel at a constant temperature of
Fudgin [204]

Answer:

After the transfer the pressure inside the 20 L vessel is 0.6 atm.

Explanation:

Considering O2 as an ideal gas, it is at an initial state (1) with V1 = 3L and P1 = 4 atm. And a final state (2) with V2 = 20L. The temperature remain constant at all the process, thus here applies the Boyle-Mariotte law. This law establishes that at a constant temperature an ideal gas the relationship between pressure and volume remain constant at all time:

P x V = k

Therefore, for this problem the step by step explanation is:

P_{1} xV_{1} = P_{2} xV_{2}

Clearing P2 and replacing

P_{2}= \frac{P_{1} xV_{1}}{V_{2} } = \frac{4atmx3L}{20L} = 0.6atm

7 0
3 years ago
How many variables are there in science
Sedaia [141]
There are three variables independent, dependent ,and controlled
7 0
3 years ago
1. A gas having the following composition is burnt under a boiler with 50% excess air.
jeka94

The composition of the stack gas are :

CH_4= 0.8713

C_3H_8 = 0.0202

CO = 0.107

<h3 /><h3>What is a mole fraction?</h3>

The ratio of the number of moles of one component of a solution or other mixture to the total number of moles representing all of the components.

Assuming 100 g of the stack gas. Calculate the mass of each species in this sample according to their percentages.

Mass of CH_4 : 70% of 100 g = 70 g

Mass of C_3H_8 : 15% of 100 g = 15 g

Mass of CO : 15% of 100 g = 15 g

Now calculate the number of moles of each species:

Number of moles of CH_4 : \frac{70 g}{16.04 g/mol} = 4.3 mole

Number of moles of C_3H_8: \frac{15 g}{144.1 g/mol} = 0.10 mole

Mass of CO : \frac{15 g}{28.01 g/mol} = 0.53 mole

Now to calculate the mole fraction of each we use the formula:

Mole fraction of CH_4: \frac{4.3}{4.935} = 0.8713

Mole fraction of C_3H_8 : \frac{0.10}{4.935} = 0.0202

Mole fraction of CO : \frac{0.53}{4.935} = 0.107

Hence, composition of the stack gas are:

CH_4 = 0.8713

C_3H_8 = 0.0202

CO = 0.107

Learn more about mole fraction here:

brainly.com/question/13135950

#SPJ1

8 0
2 years ago
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