#2
As it is given here
initial speed is
![v_i = 6 m/s](https://tex.z-dn.net/?f=v_i%20%3D%206%20m%2Fs)
After 4 seconds the final speed is
![v_f = 14 m/s](https://tex.z-dn.net/?f=v_f%20%3D%2014%20m%2Fs)
so here we can use the formula of acceleration using kinematics
![a = \frac{v_f - v_i}{t}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7Bv_f%20-%20v_i%7D%7Bt%7D)
![a = \frac{14 - 6}{4}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B14%20-%206%7D%7B4%7D)
![a = 2 m/s^2](https://tex.z-dn.net/?f=a%20%3D%202%20m%2Fs%5E2)
so here it will accelerate at 2 m/s^2 rate.
#3
As it is given here
initial it starts from rest
![v_i = 0 m/s](https://tex.z-dn.net/?f=v_i%20%3D%200%20m%2Fs)
After 2.5 seconds the final speed is
![v_f = 15 m/s](https://tex.z-dn.net/?f=v_f%20%3D%2015%20m%2Fs)
so here we can use the formula of acceleration using kinematics
![a = \frac{v_f - v_i}{t}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7Bv_f%20-%20v_i%7D%7Bt%7D)
![a = \frac{15 - 0}{2.5}](https://tex.z-dn.net/?f=a%20%3D%20%5Cfrac%7B15%20-%200%7D%7B2.5%7D)
![a = 6 m/s^2](https://tex.z-dn.net/?f=a%20%3D%206%20m%2Fs%5E2)
so here it will accelerate at 6 m/s^2 rate.
#4
i think question is not correct as in first line it is saying about a bag of trash and then in next line it is asking for the position of Jumper and bridge.