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3 years ago

14

Which of these diagrams most accurately illustrates what happens when a ray of light from underwater strikes the smooth surface

of the water at an angle of incidence greater than the critical angle?

2 answers:

Flura [38]3 years ago

5 0

Explanation :

When the ray of light from underwater strikes the smooth surface of the water at an angle of incidence greater than the critical angle, then total internal reflection occurs (TIR). The ray of light must pass from the denser medium to rarer medium.

When the angle of incidence is equal to 90, the angle formed is called critical angle.

In this case, the diagram (D) shows the angle of incidence greater than the critical angle and hence TIR occurs.

laiz [17]3 years ago

4 0

Diagram D!!!!!!!!!!!!!!!

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The Earth is approximately 150 million kilometers away from the Sun. If light travels at a speed of approximately 300,000 kilome

evablogger [386]

The correct answer to the question is 8.33 minutes.

CALCULATION:

The distance of earth from sun s = 150 million km.

We know one million = 10 lakh = $10^6$

Also 1 km = $10^3\ m$

Hence, the distance s = $150\times 10^6\times 10^3\ m$

= $15\times 10^{10}\ m$

The speed of light c = 300,000 km per second

= $3\times 10^8\ m/s$

We are asked to calculate the time.

The time of the reaching earth is calculated as -

$time=\ \frac{distance}{velocity}$

$t=\ \frac{s}{c}$

$=\ \frac{15\times 10^{10}} {3\times 10^8}\ second$

$=\ 500\ seconds$

We know one minute = 60 second.

Hence, 500 seconds = $\frac{500}{60}\ minute$

= $8.33\ minute$ [ans]

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3 years ago

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A batter hits a ball at 35 degrees above the horizontal and it is caught 4 seconds later 100 meters from home plate. What is the

Mamont248 [21]

Answer:

$u=(26.5 i + 18.5j) m/s$

Explanation:

The range of a projectile is given by the formula

$d=\frac{u^2}{g} sin 2\theta$

where in this case, we have

d = 100 m is the range

u is the initial speed (the magnitude of the initial velocity)

g = 9.8 m/s^2 is the acceleration of gravity

$\theta = 35^{\circ}$ is the angle of projection

Solving for u, we find:

$u=\sqrt{\frac{dg}{sin 2\theta}}=\sqrt{\frac{(100)(9.8)}{sin(2\cdot 35^{\circ})}}=32.3 m/s$

Now we can easily find the components of the initial velocity:

$u_x = u cos \theta = (32.3)(cos 35^{\circ})=26.5 m/s\\u_y = u sin \theta = (32.3)(sin 35^{\circ})=18.5 m/s$

So, the initial velocity of the ball is

$u=(26.5 i + 18.5 j) m/s$

where i and j are the unit vector indicating the horizontal and vertical direction.

7 0

3 years ago

You will begin with a relatively standard calculation.Consider a concave spherical mirror with a radius of curvature equal to 60

Strike441 [17]

a) 30.0 cm

For any mirror, the radius of curvature is twice the focal length:

r = 2f

where

r is the radius of curvature

f is the focal length

For the mirror in this problem, we have

r = 60.0 cm is the radius of curvature

Therefore, solving the equation above for f, we find its focal length:

$f=\frac{r}{2}=\frac{60.0 cm}{2}=30.0 cm$

b) 90 cm

The mirror equation is:

$\frac{1}{s'}=\frac{1}{f}-\frac{1}{s}$

where

s' is the distance of the image from the mirror

f is the focal length

s is the distance of the object from the mirror

For the situation in the problem, we have

f = +30.0 cm is the focal length (positive for a concave mirror)

s = 45.0 cm is the object distance from the mirror

Solving the formula for s', we find

$\frac{1}{s'}=\frac{1}{30.0 cm}-\frac{1}{45.0 cm}=0.011 cm^{-1}$

$s'=\frac{1}{0.011 cm^{-1}}=90 cm$

c) -2

The magnification of the mirror is given by

$M=-\frac{s'}{s}$

where in this problem we have

s' = 90 cm is the image distance

s = 45.0 cm is the object distance

Solving the equation, we find:

$M=-\frac{90 cm}{45 cm}=-2$

So, the magnification is -2.

d) -12.0 cm

The magnification can also be rewritten as

$M=\frac{y'}{y}$

where

y' is the height of the image

y is the heigth of the object

In this problem, we know

y = 6.0 cm is the height of the object

M = -2 is the magnification

Solving the equation for y', we find

$y'=My=(-2)(6.0 cm)=-12.0 cm$

and the negative sign means that the image is inverted.

Part e and f are exactly identical as part b) and c).

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4 years ago