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Rzqust [24]
2 years ago
12

Please can anybody tell me what are these lab equipments ​

Physics
2 answers:
lana [24]2 years ago
8 0

Answer:

hii there

5 ) tripod

6 ) test tube holder

Explanation:

Hope it helps

Have a nice day : )

olga nikolaevna [1]2 years ago
4 0

Answer:

5 is the tripoid stand

Thanks have a bangtastic day

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four forces act on an object of mass 100kg, they are 12N(N), 70N(S), 33N(E), 10N(w). calculate the reseulting acceleration of th
trapecia [35]

Answer:

0.62 m/s² at 68° S of E

Explanation:

Net force north = 12 - 70 = -58 N

Net force east = 33 - 10 = 23 N

Net force = √(-58² + 23²) = 62.3939... N

acceleration = F/m = 62.3939/100 = 0.623939... ≈ 0.62 m/s²

θ = arctan(-58/23) = -68.3691... ≈ 68° S of E

6 0
3 years ago
Please could someone explain this.
icang [17]

This problem is to let you practice using Newton's second law of motion:

Force = (mass) x (acceleration)

-- The airplane's mass when it takes off (before it burns any of its load of fuel) is 320,000 kg.

-- The force available is (240,000 N/per engine) x (4 engines) = 960,000 N.

-- Now you know ' F ' and ' mass '.  Use Newton's second law of motion to calculate the plane's acceleration.

7 0
3 years ago
A space vehicle approaches a space station in orbit. The intent of the engineers is to have the vehicle slowly approach, reducin
N76 [4]

Answer: The total momentum before the docking maneuver is mV_{1}+MV_{2} and after the docking maneuver is (m+M) U

Explanation:

Linear momentum p (generally just called momentum) is defined as mass in motion and is given by the following equation:  

p=m.v  

Where m is the mass of the object and v its velocity.

According to the conservation of momentum law:

<em>"If two objects or bodies are in a closed system and both collide, the total momentum of these two objects before the collision </em>p_{i} <em>will be the same as the total momentum of these same two objects after the collision </em>p_{f}<em>". </em>

<em />

p_{i}=p_{f}

This means, that although the momentum of each object may change after the collision, the total momentum of the system does not change.

Now, the docking of a space vehicle with the space station is an inelastic collision, which means both objects remain together after the collision.

Hence, the<u> initial momentum</u> is:

p_{i}=mV_{1}+MV_{2}

Where:

m is the mass of the vehicle

V_{1} is the velocity of th vehicle

M is the mass of the space station

V_{2} is the velocity of the space station

And the <u>final momentum</u> is:

p_{f}=(m+M)U

Where:

U is the velocity of the vehicle and space station docked

6 0
3 years ago
Read 2 more answers
Un vas plin cu lichid cântăreşte 175kg. Ceea ce reprezintă de 5 ori masa vasului gol. Ştiind că volumul interior al vasului este
Mariana [72]

a) Density of the liquid: 823.5kg/m^3

b) Weight of the liquid: 1372 N

Explanation:

Translation of the text:

<em>"A full tank with liquid weighs 175kg. Which is 5 times the mass of the empty vessel. Knowing that the inside volume of the vessel is 0.17kl, calculate: </em>

<em>a) the density of the liquid; </em>

<em>b) the weight of the liquid."</em>

a)

We know that the full tank with liquid has a total mass of M = 175 kg. We can write the total mass as

M=m_L + m_V (1)

where

m_L is the mass of the liquid

m_V is the mass of the vessel

We also know that the total mass M is 5 times the mass of the empty vessel, so we have:

M=5m_V\\m_V=\frac{M}{5}=\frac{175}{5}=35 kg

which is the mass of the empty vessel.

Therefore, we can find the mass of the liquid only using (1):

m_L=M-m_V=175-35=140 kg

The density of the liquid is given by

d=\frac{m}{V}

where

m = 140 kg (mass of the liquid)

V = 0.170 kL = 170 L = 0.170 m^3 (volume of the liquid, which is equal to the volume of the vessel)

So we get

d=\frac{140}{0.170}=823.5kg/m^3

b)

The weight of a body is given by

F=mg

where

m is its mass

g is the acceleration due to gravity

For the liquid in this problem, we have

m = 140 kg (mass)

g=9.8 m/s^2 (acceleration due to gravity)

Therefore, its weight is

F=(140)(9.8)=1372 N

Learn more about density:

brainly.com/question/5055270

brainly.com/question/8441651

#LearnwithBrainly

6 0
3 years ago
5 What is the kinetic energy of a 28 kg car moving at a velocity of 7 m/s O 1963 98 686 J O 350 nocter diagram, at which point w
Shtirlitz [24]

Answer:

98 joules

Explanation:

1/2 of 28 = 14

14 multiply by 7= 98 joules

4 0
3 years ago
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