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SOVA2 [1]
3 years ago
9

If an electronic circuit experiences a loss of 3 decibels with an input power of 6 watts, what would its output power be, to the

nearest watt?
Physics
2 answers:
telo118 [61]3 years ago
7 0

Answer:

Output Power = 3 Watt

Explanation:

As we know that loss of 3 dB occurs when it is having input of 6 Watts

So here we can say that

3 dB = 10 Log\frac{P_{in}}{P_{out}}

now we know that

P_{in} = 6 Watt

so we will have

0.30 = Log \frac{6}{P_{out}}

now we have

P_{out} = 6 \times 10^{-0.30}

P_{out} = 3 Watt

So output power will be 3 Watt

agasfer [191]3 years ago
4 0

Answer:

Output power of the circuit is 3 Watt.

Given:

loss in decibles = 3 dB

Input power = 6 Watt

To find:

Output power = ?

Formula used:

Output power = Input power × loss in ratio

Solution:

3 dB loss = 0.5 ratio

Output power is given by,

Output power = Input power × loss in ratio

Output power = 6 × 0.5

Output power = 3 Watt

Thus, output power of the circuit is 3 Watt.

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Answer:

E. Kepler's second law says the planet must move fastest when it is closest, not  when it is farthest away.

Explanation:

We can answer this question by using Kepler's second law of planetary motion, which states that:

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This means that when a planet is further away from the Sun, it will move slower (because the line is longer, so it must move slower), while when the planet is closer to the Sun, it will move faster (because the line is shorter, so it must move faster).

In the text of this problem, it is written that the planet moves at 31 km/s when is close to the star and 35 km/s when it is farthest: this is in disagreement with what we said above, therefore the correct option is

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3 years ago
Examples of applied force
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Answer:

Push - The most common form of force is a push through physical contact (like a lawnmower or shopping cart)

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Explanation:

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3 years ago
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3 years ago
I NEED MAJOR HELP ON THIS AS WELL PLEASE SOMEONE HELP ME
yuradex [85]

Answer:

The total distance is  130.2 [m]

Explanation:

In order to solve this problem we must use the expressions of kinematics. The clue to solve this problem is that the cart starts from rest, i.e. its initial speed is zero.

v_{f} =v_{o} +(a*t)

where:

Vf = final velocity [m/s]

Vo = initial velocity = 0

a = acceleration = 3 [m/s²]

t = time = 8[s]

Vf = 0 + (3*8)

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With this velocity we can calculate the displacement using the following expression.

v_{f} ^{2} =v_{o} ^{2} +2*a*x

where

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x = 576/(6)

x = 96 [m]

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The other important clue to solve this problem in the second part is that the final velocity is now the initial velocity.

We must calculate the final velocity.

v_{f}= v_{i} -(a*t)

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t = time = 15 [s]

Vf = 24 - (1.6*15)

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With this velocity, we can calculate the displacement using the following expression.

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where

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Note: The negative sign in the equations is because the car is desaccelerating, it means its velocity is decreasing.

Therefore the total distance is Xt = 34.2 + 96 = 130.2 [m].

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3 years ago
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katen-ka-za [31]

Answer:

It would be 2600

Explanation:

M/S stands for meters per second. If it moved 1 meter for 2600 seconds, than it would be 2600. You just multiply 2600 by 1! I hope this helps :D

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