Answer:
t = 15.42 s
Step-by-step explanation:
A rocket is launched from a tower. The height of the rocket, y in feet, is related to the time after launch, x in seconds, by the given equation.

We ned to find the time when the rocket will the ground. For this, y = 0

It is a quadratic equation whose solution is given by :

Here, a = -16, b = 242 and c = 73

Neglecting negative value.
So, it will hit the ground in 15.42 s.
A) (2, 7) (0, 3)
B) (1,5) (3, 3)
C) inconsistent because it starts to go down.
D) (0,3) (1, 5) (2,7) (3,3)
I hope this helped
Its 12 because you do 10.5/21=x/24
Answer:
24
Step-by-step explanation:
Step 1: We make the assumption that 120 is 100% since it is our output value.
Step 2: We next represent the value we seek with $x$.
Step 3: From step 1, it follows that $100\%=120$.
Step 4: In the same vein, $x\%=28.8$.
Step 5: This gives us a pair of simple equations:
$100\%=120(1)$.
$x\%=28.8(2)$.
Step 6: By simply dividing equation 1 by equation 2 and taking note of the fact that both the LHS
(left hand side) of both equations have the same unit (%); we have
$\frac{100\%}{x\%}=\frac{120}{28.8}$