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2 years ago

Hello

Mathematics

2 answers:

hjlf2 years ago

4 0

Answer:

1/10

Step-by-step explanation:

1 + 1/2 = 1 1/2

1 - 1/8 = 7/8

1 + 1/5 = 1 1/5

1 - 1/3 = 2/3

1 + 1/10 = 1 1/10

One and one tenth is closest to one because one tenth is the smallest amount that would need to be added or taken away to get exactly one. Hope I helped!

Licemer1 [7]2 years ago

3 0

Answer:

Step-by-step explanation:

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2. 3x + 2y = 22<br> 5x – 2y = 42

hammer [34]

Step-by-step explanation:

3x+2y=22

5x-2y=42

by adding both equation

8x. =64

x=64/8=8

substituting x in the 1st equation

we get,

3*8+2y=22

24+2y=22

2y=22-24

y=-2/2=-1

therefore,

x=8

y=-1

6 0

2 years ago

Read 2 more answers

Find the range of the function y=-x^2-3x when the domain is {-5, 0, 2}

ankoles [38]

The range of the function y = -x² - 3x when the domain is {-5,0,2} is:

{-10, 0}.

<h3>What is the range of a function?</h3>

The range of a function is the set that contains the output values for the given domain of the function.

In this problem, the domain is:

{-5,0,2}.

Hence the output values are:

-(-5)² - 3(-5) = -25 + 15 = -10.

-(0)² - 3(0) = 0.

-(2)² - 3(2) = -4 + -6 = -10.

Hence the range is:

{-10, 0}.

-10 repeats, but goes only once on the range.

More can be learned about the range of a function at brainly.com/question/10891721

#SPJ1

7 0

1 year ago

Can someone please help!

romanna [79]

Answer:

The value of x is 49 and the value of AB is 90

Step-by-step explanation:

You know that AB and DE are congruent. That information is given to you.

You set the equations equal to each other and then solve.

2x - 8 = x + 38

Subtract x

x - 8 = 38

Add 8.

x = 49

Plug back into 2x - 8 to find the value of AB

2 times 49 - 8

98 - 8

4 0

2 years ago

Use the given information to find the exact value of the trigonometric function

eimsori [14]

$\begin{gathered} \csc \theta=-\frac{6}{5} \\ \tan \theta>0 \\ \cos \frac{\theta}{2}=\text{?} \end{gathered}$

Half Angle Formula

$\cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}}$ $\tan \theta>0\text{ and csc}\theta\text{ is negative in the third quadrant}$ $\begin{gathered} \csc \theta=-\frac{6}{5}=\frac{r}{y} \\ x^2+y^2=r^2 \\ x=\pm\sqrt[\square]{r^2-y^2} \\ x=\pm\sqrt[\square]{6^2-(-5)^2} \\ x=\pm\sqrt[\square]{36-25} \\ x=\pm\sqrt[\square]{11} \\ \text{x is negative since the angle is on the 3rd quadrant} \end{gathered}$ $\begin{gathered} \cos \theta=\frac{x}{r}=\frac{-\sqrt[\square]{11}}{6} \\ \cos \frac{\theta}{2}=\pm\sqrt[\square]{\frac{1+\cos\theta}{2}} \\ \cos \frac{\theta}{2}is\text{ also negative in the 3rd quadrant} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{1+\frac{-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{\frac{6-\sqrt[\square]{11}}{6}}{2}} \\ \cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}} \\ \\ \end{gathered}$

Answer:

$\cos \frac{\theta}{2}=-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}$

Checking:

$\begin{gathered} \frac{\theta}{2}=\cos ^{-1}(-\sqrt[\square]{\frac{6-\sqrt[\square]{11}}{12}}) \\ \frac{\theta}{2}=118.22^{\circ} \\ \theta=236.44^{\circ}\text{ (3rd quadrant)} \end{gathered}$

Also,

$\csc \theta=\frac{1}{\sin\theta}=\frac{1}{\sin (236.44)}=-\frac{6}{5}\text{ QED}$

The answer is none of the choices

7 0

11 months ago

What is the sum of -6 4/5 and 6 4/5 ?

daser333 [38]

Answer:

Step-by-step explanation:

-6 4/5 + 6 4/5 equals zero.

3 0

3 years ago

Read 2 more answers