Answer:
Step-by-step explanation:
EF - base1
HG - base2
J-midpoint of EH
K-midpoint of FG
We are solving it by using formula:
JK=(base1+base2):2
25=(3x+2+7x-2):2
25*2=10x
50=10x
x=50:10
x=5
Good luck!
Let the least possible value of the smallest of 99 cosecutive integers be x and let the number whose cube is the sum be p, then

By substitution, we have that

and

.
Therefore, <span>the least possible value of the smallest of 99 consecutive positive integers whose sum is a perfect cube is 314.</span>
Answer:
the answer is 45
Step-by-step explanation:
Answer: That would be xy−4x <3 hope it helps
Step-by-step explanation: all u have to do is multiply the polynomials