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3 years ago

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An element has an atomic weight of 137 g/mol and a BCC crystal structure. If the volume density of the element is 2.2 g/cm3 what

is the radius (in nm) of the atom?

1 answer:

kap26 [50]3 years ago

7 0

Explanation:

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5 g of gold and 25 g of silver are mixed to form a single-phase ideal solid solution. (a) how many moles of solution are there?

worty [1.4K]

Mole fraction for silver= 0.2317643/0.3079193

= 0.7526787

Mole fraction for gold=0.076155/0.3079193

=0.2473212

What is Molar Fraction?

The mole fraction is the product of the number of molecules of a specific component in a mixture and its total molecular weight. It serves as a means of indicating how concentrated a solution is.

It is a unit of concentration, defined as the product of the moles of a component and the moles of the entire solution. When all the parts of a solution are summed up, their mole fraction equals 1.

molar mass of silver = 107.8682g/mol

Molar mass of gold= 196.96657g/mol

Therefore mole = mass/molar mass

For silver: 25g/107.8682g/mol = 0.2317643mol

For gold: 15g/196.96657g/mol= 0.076155mol

Total number of mole= 0.2317643+0.076155

= 0.30791193mol

Mole fraction for silver= 0.2317643/0.3079193

= 0.7526787

Mole fraction for gold=0.076155/0.3079193

=0.2473212

Learn more about Mole Fraction from given link

brainly.com/question/28590918

#SPJ4

3 0

9 months ago

How is glaas made ? I reallyt don't know

Vlad1618 [11]

Glass is formed when sand or rocks are heated to high temperatures and then cooled rapidly to create glass. i learned that from minecraf,t when u put sand in a furnace lol

4 0

3 years ago

The microwaves in an oven are of a specific frequency that will heat the water molecules contained in food. (This is why most pl

statuscvo [17]

Answer:

2E-24

Explanation:

8 0

3 years ago

5g of a mixture of KOH and KCl with water form a solution of 250mL. We have 25ml of this solution and we mix it with 14,3mL of H

cricket20 [7]

We know that the number of moles HCl in 14.3mL of 0.1M HCl can be found by multiplying the volume (in L) by the concentration (in M).
(0.0143L HCl)x(0.1M HCl)=0.00143 moles HCl

Since HCl reacts with KOH in a one to one molar ratio (KOH+HCl⇒H₂O+KCl), the number of moles HCl used to neutralize KOH is the number of moles KOH. Therefore the 25mL solution had to contain 0.00143mol KOH.

To find the mass of KOH in the original mixture you have to divide the number of moles of KOH by the 0.025L to find the molarity of the KOH solution..
(0.00143mol KOH)/(0.025L)=0.0572M KOH

Since the morality does not change when you take some of the solution away, we know that the 250mL solution also had a molarity of 0.0572. That being said you can find the number of moles the mixture had by multiplying 0.0572M KOH by 0.250L to get the number of moles of KOH.
(0.0572M KOH)x(0.250L)=0.0143mol KOH

Now you can find the mass of the KOH by multiplying it by its molar mass of 56.1g/mol.
0.0143molx56.1g/mol=0.802g KOH

Finally you can calulate the percent KOH of the original mixture by dividing the mass of the KOH by 5g.
0.802g/5g=0.1604
the original mixture was 16% KOH

I hope this helps.

7 0

3 years ago

Can you quess my Hogwarts house? Please explain why you think that and I will give brainliest

vladimir1956 [14]

Answer:

I prob can bc I'm a bad b*tch

lol

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3 years ago