Answer:
25 grams of Mg(OH)2 will be produced by 14.424 gram of Mg3N2
Explanation:
The balanced equation is
Mg3N2 + 6H2O -> 3Mg(OH)2 + 2NH3
Molecular weight of magnesium nitride = 100.9494 g/mol
Molecular weight of magnesium hydroxide = 58.3197 g/mol
one mole of Mg3N2 produces three moles of 3Mg(OH)2
100.9494 g/mol of Mg3N2 produces 3* 58.3197 g/mol of Mg(OH)2
1 gram of Mg3N2 produces
grams of Mg(OH)2
Or 1.733 grams of Mg(OH)2 will be produced by 1 gram of Mg3N2
25 grams of Mg(OH)2 will be produced by 14.424 gram of Mg3N2
Nothing in particular determines the name of an element, it could range from who discovered it to where it was discovered!
Answer:
31.7 °C
Explanation:
Charles law states that for volume of a gas is directly proportional to the absolute temperature for a fixed amount of gas at constant pressure
we can use the following equation
V1/T1 = V2/T2
where V1 is volume and T1 is temperature at first instance
V2 is volume and T2 is temperature at second instance
temperature should be in kelvin scale
T1 - 0 °C + 273 = 273 K
substituting the values in the equation
22.4 L / 273 K = 25.0 L / T2
T2 = 304.7 K
temperature in celcius is - 304.7 K - 273 = 31.7 °C
the gas must be 31.7 °C to reach a volume of 25.0 L
When 6.85×10⁵ cal is converted to kilojoules, the result obtained is 2866.04 KJ
<h3>Data obtained from the question </h3>
- Energy (cal) = 6.85×10⁵ cal
- Energy (KJ) =?
<h3>Conversion scale </h3>
1 cal = 0.004184 KJ
<h3>How to convert 6.85×10⁵ cal to kilojoules</h3>
1 cal = 0.004184 KJ
Therefore,
6.85×10⁵ cal = 6.85×10⁵ × 0.004184
6.85×10⁵ cal = 2866.04 KJ
Thus, 6.85×10⁵ cal is equivalent to 2866.04 KJ
Learn more about conversion:
brainly.com/question/2139943
The reaction will be: FeBr2 + K --> KBr + Fe
Balancing gives: FeBr2 + 2K --> 2KBr + Fe
The molar mass of FeBr2 is 55.85 + 2*79.9 = 215.65 g/mol.
We divide 40 g / 215.65 g/mol = 0.185 mol FeBr2
Based on stoichiometry:
(0.185 mol FeBr2)(2 mol KBr/1 mol FeBr2) = 0.370 mol KBr
