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gladu [14]
3 years ago
7

Is copper ii sulphate (solution) blue or green?

Chemistry
1 answer:
slavikrds [6]3 years ago
8 0
Copper II sulfate solution is blue.
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which conversion factor do you use first to calculate the number of grams of fecl3 produced by the reaction of 30.3 g of fe with
Alexeev081 [22]

Answer:

30

Explanation:

8 0
3 years ago
Consider the reaction N2(g) + 3H2(g) → 2NH3(g) Suppose that at a particular moment during the reaction, molecular hydrogen is re
rosijanka [135]

Answer:

The solution to the question is as follows

(a) The rate of ammonia formation = 0.061 M/s

(b) the rate of N₂ consumption = 0.0303 M/s

Explanation:

(a) To solve the question we note that the reaction consists of one mole of N₂ combining with three moles of H₂ to form 2 moles of NH₃

N₂(g) + 3H₂(g) → 2NH₃(g)

The rate of reaction of molecular hydrogen = 0.091 M/s, hence we have

3 moles of H₂ reacts to form 2 moles of NH₃, therefore

0.091 M of H₂ will react to form 2/3 × 0.091 M or 0.061 M of NH₃

Hence the rate of ammonia formation is 0.061 M/s

(b) From the reaction equation we have 3 moles of H₂ and one mole of N₂ being consumed at the same time hence

0.091 M of H₂ is consumed simultaneously with 1/3 × 0.091 M or 0.0303 M of N₂

Therefore the rate of consumption of N₂ = 0.0303 M/s

6 0
3 years ago
The number of moles of H2O which contains 4g of oxygen?
satela [25.4K]

Answer:

16G = 1 mole ; then 4G = how many moles? 4/16 = 0.25 mole; That means 4 grams of oxygen is 0.25 moles.

4 0
3 years ago
Read 2 more answers
Are two double bonds in<br> uble dash.<br> :0=C=O<br> NO2-
LenaWriter [7]

Answer:

Yes

Explanation:

There are in double dash :) ( = )

5 0
3 years ago
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The ksp of cadmium hydroxide, cd(oh)2, is 7.20 × 10-15. calculate the solubility of this compound in g/l.
olga nikolaevna [1]
When the solubility is the amount of solute that dissolved in a unit volume of the solvent.

and when the balanced reaction equation is:

so, by using the ICE table:

            Cd(OH)2(s) ↔  Cd2+  +  2OH- 

initial                               0             0

change                          +X           +2X

Equ                                  X             2X

so the Ksp expression = [Cd2+] [OH-]^2 

and we have Ksp = 7.2 x 10^-15

and when we assume the solubility = X
  
by substitution:

7.2 x 10^-15 = (X) (2X)^2

7.2 x 10^-15 = X*4X^2

7.2 x 10^-15 = 4X^3

∴X = ∛(7.2x10^-15)/4

      = 1.22 x 10^-5 M

∴ the solubility = X = 1.22 x 10^-5 M
6 0
4 years ago
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