The first step Niven has to do
in his calculation is to Balanced the chemical equation. The answer is letter
A. The key in the balancing of chemical reaction is to make sure that you got
the exact chemical formula of the substance that is reacting and the yielded
product. After getting the formula, identify first the hardest element/atom to
be balanced such as Na, Zn, Cl, etc. Then proceed to the easier ones such as O,
H. Make sure to not the atoms present in the molecule of the substance.
x21 +ANSWER
(i) Ne-22
(ii)1s2s22p6
(iii)21.3
An element X exists in three forms A, B and C in the ratio 1:2:3. If C has 10 protons and the number of neutrons in A, B and C are 10, 11 and 12 respectively,Give the following:(i) Representation of form C of the element X(ii) Electronic configuration of form B of the element(iii) Calculate the average atomic mass.
(i)C has 10 protons and 12 neutrons so a mass of 10 +12 =22
element 10 is Neon (Ne) so this isotope is Ne-22
(ii) they all have the sane atomic number so the same number of electrons
with an electronic structure of 1s2s22p6
(iii) A weighs 20, B weighs 21, C weighs 22
the ratio is 1:2:3
weighted average weight is therefor
(1X20 +2X21 +3X22)/6 =21.3
Answer:
Balancing Nuclear Equations
To balance a nuclear equation, the mass number and atomic numbers of all particles on either side of the arrow must be equal.
Explanation:
follows:
6
3
Li
+
2
1
H
→
4
2
He
+
?
To balance the equation above for mass, charge, and mass number, the second nucleus on the right side must have atomic number 2 and mass number 4; it is therefore also helium-4. The complete equation therefore reads:
6
3
Li
+
2
1
H
→
4
2
He
+
4
2
He
Or, more simply:
6
3
Li
+
2
1
H
→
2
4
2
He
image
Lithium-6 plus deuterium gives two helium-4s.: The visual representation of the equation we used as an example.
Compact
I think it’s C atomic radius and numbers of unshielded protons
The metals are to the left of the line (except for hydrogen, which is a nonmetal), the nonmetals are to the right of the line, and the elements immediately adjacent to the line are the metalloids.
hope it helps...!!!
