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Illusion [34]
3 years ago
15

Question 1 of 10 What happens when a solid becomes a liquid?

Chemistry
2 answers:
Natalija [7]3 years ago
6 0

Answer:it dissolves and evaporates

Explanation:

GREYUIT [131]3 years ago
6 0
It will dissolve and then start to evaporate
You might be interested in
Element
Svetllana [295]

Answer:

Number of moles = 10.6 mol

Explanation:

Given data:

Molar mass of H = 1.008 g/mol

Molar mass of C = 12.01 g/mol

Molar mass of O = 16.00 g/mol

Mass of citric acid = 2.03 kg (2.03×1000 = 2030 g)

Number of moles of citric acid = ?

Solution:

Formula:

Number of moles = mass/molar mass

Now we will calculate the molar mass of citric acid:

C₆H₈O₇ = (12.01× 6) + (1.008×8) + (16.00×7)

C₆H₈O₇ = 72.06 + 8.064+112

C₆H₈O₇ = 192.124g/mol

Number of moles = 2030 g/ 192.124g/mol

Number of moles = 10.6 mol

7 0
3 years ago
HELP HELP PLS !! <br> 5N<br> 21N
Sonja [21]

Answer:

Check the image file attached

Explanation:

6 0
3 years ago
Which of the following reactions does the coenzyme biotin catalyze?
Papessa [141]

Answer:

c. decarboxylation of an a-keto acid.

Explanation:

Decarboxylation refers to the removal of the carboxyl group from a carboxylic acid and thus releasing carbon dioxide. Decarboxylases are enzymes that speed up the removal of the carboxyl group from acids. These reactants could be amino acids, alpha-keto acids, and beta-keto acids. Biotin is known to catalyze the decarboxylation of malonyl CoA to acetyl CoA during fatty acid synthesis.

Malonyl CoA is converted to acetyl CoA after decarboxylation assisted by biotin also known as Vitamin H. Alpha keto acids are involved in fatty acids synthesis and Malonyl CoA is an alpha-keto acid because the keto group is located in the first carbon near the carboxylic acid group. Keto acids have both a carboxyl group and a ketone group.

5 0
3 years ago
What is the enthalpy change (in kj) of a chemical reaction that raises the temperature of 250.0 ml of solution having a density
Pepsi [2]
<span>250 ml * 1.25 g/ml * 3.74 j/g-K * 9.2 K = 10.752 kJ Pretty much, all you need to do here is multiply all of these out to get your final answer. Not all questions are this easy, but this is certainly one of them.</span>
3 0
3 years ago
Read 2 more answers
The amount of radioactive carbon-14 in a sample is measured using a Geiger counter, which records each disintegration of an atom
sergij07 [2.7K]

Answer:

4121 years

Explanation:

From;

0.693/t1/2 = 2.303/t log No/N

t1/2= half life of the carbon-14

No= count rate of the living tissue

N= count rate of the sample

t = age of the sample

0.693/5730 =2.303/t log (13.5/8.2)

1.21 * 10^-4 = 2.303/t * 0.2165

1.21 * 10^-4 = 0.4986/t

t = 0.4986/1.21 * 10^-4

t = 4121 years

7 0
3 years ago
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