1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Reil [10]
3 years ago
13

Calculate the approximate volume of a 0.6000mol sample of gas at 288.15K and a pressure of 1.10atm.

Chemistry
1 answer:
11111nata11111 [884]3 years ago
6 0

Answer:

The volume of the sample of the gas is found to be 12.90 L.

Explanation:

Given pressure of the gas = P = 1.10 atm

Number of moles of gas = n = 0.6000 mole

Temperature = T = 288.15 K

Assuming the volume of the gas to be V liters

The ideal gas equation is shown below

\textrm{PV} =\textrm{nRT} \\1.10 \textrm{ atm}\times V \textrm{ L} = 0.6000 \textrm{ mole}\times 0.0821 \textrm{ L.atm.mol}^{-1}.K^{-1}\times 288.5\textrm{K} \\\textrm{V} = 12.90 \textrm{ L}

Volume occupied by gas = 12.90 L

You might be interested in
Do you think your meal would allow your cells to sufficiently build your cell
expeople1 [14]

Answer:

Cells are the fundamental units of life ' the bricks from which all your. which are built of your cells, will become compromised, and you can. of these new cells from the nutrients you get in your food is one way. Let's take a look inside one of your cells and see what the nutrients really do.

Explanation:

8 0
3 years ago
What steps should you take to respond to an accident?
Marina86 [1]
If it’s multiple answers then it’s A,C,D. If it’s only one answer then your best answer is A. Because you always report accidents to an authority so that they can figure out how to solve the problem.
5 0
2 years ago
Consider the combustion of octane (C8H18)
sesenic [268]
The balanced equation for the above reaction is as follows;
2C₈H₁₈ + 25O₂ --->  16CO₂  + 18H₂O
stoichiometry of octane to CO₂ is 2:16
number of C₈H₁₈ moles reacted - 191.6 g / 114 g/mol = 1.68 mol
when 2 mol of octane reacts it forms 16 mol of CO₂
therefore when 1.68 mol of octane reacts - it forms 16/2 x 1.68 = 13.45 mol of CO₂
number of CO₂ moles formed - 13.45 mol
therefore mass of CO₂ formed - 13.45 mol x 44 g/mol = 591.8 g
 mass of CO₂ formed is 591.8 g
3 0
3 years ago
Natural gas and petroleum are mostly alkanes t/f
dolphi86 [110]
Been a year since i was in chem but my money is on true
5 0
3 years ago
Read 2 more answers
The alveoli are surrounded by __________ carrying blood to and from the heart.
natka813 [3]
The alveoli are surrounded<span> by tiny blood vessels, called capillaries. The </span>alveoli<span> and capillaries both have very thin walls, which allow the oxygen to pass from the </span>alveoli<span>to the blood. The capillaries then connect to larger blood vessels, called veins, which bring the oxygenated blood from the lungs to the heart.</span>
4 0
3 years ago
Other questions:
  • NEED HELP ASAP WILL GIVE BRAINLIEST.<br> What is the element that has the atomic number of 17?
    14·1 answer
  • Write reaction showing how each of the buffers would neutralize added naoh. hcho2 and nacho2
    10·1 answer
  • How does an atom-88 become a strontium ion with a +2 charge?
    7·1 answer
  • Consider the reactionI2(g) + Cl2(g)2ICl(g)Using standard thermodynamic data at 298K, calculate the entropy change for the surrou
    12·1 answer
  • What is 9.871 x 10^-3 in standard form? *
    14·2 answers
  • After doing multiple titrations, your NaOH solution is determined to have a mean concentration value of 0.100 M. Given you are t
    12·1 answer
  • A sample of helium gas has a volume of 2.75 L at STP. How many grams of He are present?
    11·1 answer
  • A 0.040 kg ball tied to a string moves in a circle that has a radius of 0.700 m. If the ball is accelerating at 43.2 m/s2, what
    14·1 answer
  • 2NaBr + 1Cl2 = 2NaCl + Br2 reaction type
    13·1 answer
  • Solids , liquids are the three different states of matter However , they show some similarities of their properties
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!